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grandymaker [24]
4 years ago
14

How many four digit numbers (0 to 9,999)

Mathematics
1 answer:
Crazy boy [7]4 years ago
5 0
9000 if you don't allow numbers with leading zeros, such as 0,000.

10,000 if you do allow numbers with leading zeros.
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what do you notice about the corresponding coordinates of the preimage and image after a reflection across the x-axis
valkas [14]
The x remains the same while the y changes sign. So if it’s (1,4) the reflection will be (1,-4). Hope fully that helps.
8 0
3 years ago
Isolate c in the equation a=b(1/c-1/d)
Irina-Kira [14]
A=b/c -b/d
a+b/d=b/c
(da+b)/d=b/c
db=(da+b)c
c=db/da+b
5 0
3 years ago
Does this graph below represent a function? (Yes or no)
Whitepunk [10]

Answer:yes

Step-by-step explanation: it represents a function

4 0
3 years ago
HELP<br><br><br><br><br> QUICK<br><br><br><br><br> LOL THANKS !!!
Anon25 [30]

Answer:

0.6

Step-by-step explanation:

The x increases by 5, while y increases by 3

Lets use the method, which is \frac{rise}{run}.

Keep in mind that x goes horizontally along the axis, while y goes vertically on the axis.

So plug the numbers in.

\frac{3}{5} = 0.6

Hence, the constant proportionality is 0.6.

8 0
3 years ago
Read 2 more answers
| x-3 | &lt; x-3<br><br> can someone give a step by step process on how to do this?
statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)  

2. Solve each equation separately

(a) Equation (1)

\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}

(b) Equation (2)

\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &

For example, if x = 0, we get  

|0 - 3| < 0 - 3 or

3 < -3

4 0
3 years ago
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