Solution
write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3
r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2
2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2
Answer: 1.48
Step-by-step explanation:
ANSWER
5
EXPLANATION
The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is

To find the time when the ball hit the ground,we equate the function to zero.

Factor to obtain;

Apply the zero product property to obtain,


t=0 or t=5.1 to the nearest tenth.
Therefore the ball hits the ground after approximately 5 seconds.
Answer:
uhhh ok
Step-by-step explanation: