Answer is B - Exothermic because energy is released
Answer:
140.85 is the correct answer
Answer:
the electric field strength on the second one is 2.67 N/C.
Explanation:
the electric fiel on the first one is:
E1 = k×q/(r^2)
r^2 = k×q/(E1)
= (9×10^9)×(q)/(24.0)
= 375000000q
then the electric field on the second one is:
E2 = k×q/(R^2)
we know that R = 3r
R^2 = 9×r^2
E2 = k×q/(9×r^2)
= k×q/(9×375000000q)
= k/(9×375000000)
= (9×10^9)/(9×375000000)
= 2.67 N/C
Therefore, the electric field strength on the second one is 2.67 N/C.
Answer:
-0.9 m/s²
Explanation:
t = Time taken by the hockey puck = 7 seconds
u = Initial velocity of the hockey puck = 13 m/s
v = Final velocity of the hockey puck = 6.7 m/s
a = Acceleration of the hockey puck
Equation of motion
The acceleration of the hockey puck in the seven seconds is -0.9 m/s²
The acceleration due to gravity is not needed to find the acceleration of the puck.