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Jet001 [13]
4 years ago
8

A pulley 326 mm in diameter and rotating initially at 4.00 revolutions per second receives a constant angular acceleration of 2.

25 radians per second squared by a drive belt. What is the linear velocity of the belt after 5.00 seconds
Physics
1 answer:
mixas84 [53]4 years ago
3 0

Answer:

The linear velocity, v = 5.93 m/s

Explanation:

To find the linear velocity after 5 seconds, we find its angular velocity after 5 seconds using

ω' = ω + αt where ω = initial angular speed = 4.00 rev/s = 4.00 × 2π rad/s = 25.13 rad/s, ω' =  = final angular speed, α = angular acceleration = 2.25 rad/s² and t = time = 5.00 s

ω' = ω + αt

= 25.13 rad/s + 2.25 rad/s² × 5.00 s

= 25.13 rad/s + 11.25 rad/s

= 36.38 rad/s

The linear velocity v is gotten from v = rω' where r = radius of pulley = 326 mm/2 = 163 mm = 0.163 m

v = rω'

= 0.163 m × 36.38 rad/s

= 5.93 m/s

So, the linear velocity  v = 5.93 m/s

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Two Objects of the same size will always have the same mass” Is this statement correct?
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No, they won't, mass coincides with density and objects have different densities a one pound lead ball would be smaller than a one pound copper one.

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3 years ago
A circular coil has a 8.79 cm radius and consists of 42.0 closely wound turns of wire. An externally produced magnetic field of
OverLord2011 [107]

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8 0
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Boyles law<br> squeezing a balloon is one way to burst it. Why? ...?
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6 0
4 years ago
A mass of 3.0 kg rests on a smooth surface inclined 34° above the horizontal. It is kept from sliding down the plane by a spring
azamat

Answer:

The spring stretched by x = 13.7 cm

Explanation:

Given data

Mass = 3 kg

k = 120 \frac{N}{m}

Angle \theta = 34°

From the free body diagram

Force acting on the box = mg sin\theta

⇒ F = 3 × 9.81 × \sin34

⇒ F = 16.45 N ------- (1)

Since box is attached with the spring so a spring force also acts on the box.

F_{sp} = k x

F_{sp} = 120 x -------- (2)

The net force acting on the body is given by

F_{net} = ma

Since acceleration of the box is zero so

F_{net} = 0

F - F_{sp} = 0

F = F_{sp}

Put the values from equation (1) & (2) we get

16.45 = 120x

x = 0.137 m

x = 13.7 cm

Therefore the spring stretched by x = 13.7 cm

3 0
3 years ago
What is the minimum amount of energy required to completely melt a 7.25-kg lead brick which has a starting temperature of 18.0 °
Delvig [45]

Answer: c. 4.56 × 105 J

Explanation:

Given that

mass of lead brick, m= 7.25kg

Temperature T1 =  18.0 °C

Temperature T2 = 328 °C

specific heat capacity of lead, c = 128 J/(kg∙C°)

latent heat of fusion Lfusion =23,200 J/kg

Amount of energy Q =?

Using the formulae

Amount of energy ,Q =mc ( T2-T1)+ mLfusion

7.25kg x 128 J/(kg∙C°) x (328-18°C) + 7.25kg x 23200 J/kg

=455880J

=4.56 x 10^5 J

5 0
3 years ago
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