6/14=x/20 cross multiply and get 14x=120 divide and get 8 2/30
The answer is not defined.
Explanation:
The given matrix is ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
The matrix ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 2 columns.
Also, the matrix ![$\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 1 column.
Since, the matrices can be added only if they have the same dimensions.
In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.
Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.
Hence, the addition of these two matrices is not defined.
Answer:
The answer is 55 6/9, but when simplified, it is 55 1/3
Answer:
Each poodle = $300
Each Cat = $150
Step-by-step explanation:
Let number of poodles be P and number of cats be C
"if he buys 3 pooples and 2 cats he will spend 1200" mathematically:
3P + 2C = 1200-------eq 1
"2 poodles and 3 cats he will spend 1050" mathematically:
2P + 3C = 1050 ------eq 2
So now we have a system of 2 equations with 2 unknowns, we'll solve by elimination
eq 1 x 3 : 3 (3P + 2C) = 3 (1200)
9P + 6C = 3600 ------ eq 3
eq 2 x 2: 2(2P + 3C) = 2(1050)
4P + 6C = 2100---------eq 4
By elimination : eq 3 - eq 4
(9P + 6C) - (4P + 6C) = 3600 - 2100
9P - 4P = 1500
5P = 1500
P = 300 (answer)
Substituting back into eq 1
3(300) + 2C = 1200
900 + 2C = 1200
2C = 1200 - 900
2C = 300
C = 150(answer)
<span>pennies = 0.01 $
nickels = 0.05 $
dimes = 0.1 $
quarters = 0.25 $
We must write the system of equations that best suits this problem and solve it:
Let:
x = pennies
y = nickels
z = dimes
w = quarters
Writing the equations
0.01x + 0.05y + 0.1z + 0.25w = 3.71
I have twice as many dimes as nickels
z = 2y
two more nickels than quarters
y = w + 2
three fewer pennies than three times the number of nickels
x = 3y-3.
Solving the system of equations:
x = 21
y = 8
z = 16
w = 6
answer
He has
21 pennies
8 nickels
16 dimes
6 quarters
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