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3 years ago

In right triangle XYZ, ∠Y is the right angle and m∠X = 60°. If YZ = 4, what is XY?

Mathematics

1 answer:

daser333 [38]3 years ago

6 0

Answer:

B is the best answer

The question is illustrated with the attached figure.

Required

Determine XY

To solve for XY, we make use of the tan function, which states that:

tan\theta = \frac{Opposite}{Hypotenuse}tanθ=

Hypotenuse

Opposite

In this case:

tan\ 60= \frac{YZ}{XY}tan 60=

Substitute 4 for YZ

tan\ 60= \frac{4}{XY}tan 60=

Make XY the subject

XY= \frac{4}{tan\ 60}XY=

tan 60

tan\ 60 =\sqrt 3tan 60=

So, the expression becomes:

XY = \frac{4}{\sqrt 3}XY=

Rationalize:

XY = \frac{4 * \sqrt 3}{\sqrt 3 * \sqrt 3}XY=

∗

4∗

XY = \frac{4\sqrt 3}{3}XY=

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A given line has the equation 10x + 2y = −2.

worty [1.4K]

The equation is $\boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }$

<h3>Further explanation </h3>

This case asking the end result in the form of a slope-intercept.

<u>Step-1: find out the gradient. </u>

10x + 2y = -2

We isolate the y variable on the left side. Subtract both sides by 10x, we get:

2y = - 10x - 2

Divide both sides by two

y = -5x -1

The slope-intercept form is $\boxed{ \ y = mx + c \ }$ , with the coefficient m as a gradient. Therefore, the gradient is m = -5.

If you want a shortcut to find a gradient from the standard form, implement this:

$\boxed{ \ ax + by = k \rightarrow m = - \frac{a}{b} \ }$

10x + 2y = −2 ⇒ a = 10, b = 2

$\boxed{m = - \frac{10}{2} \rightarrow m = -5}$

<u>Step-2:</u> the conditions of the two parallel lines

The gradient of parallel lines is the same $\boxed{ \ m_1 = m_2 \ }$ . So $\boxed{m_1 = m_2 = -5}.$

<u>Final step:</u> figure out the equation, in slope-intercept form, of the parallel line to the given line and passes through the point (0, 12)

We use the point-slope form.

$\boxed{ \ \boxed{ \ y - y_1 = m(x - x_1)} \ }$

Given that

m = -5
(x₁, y₁) = (0, 12)

y - 12 = - 5(x - 0)

y - 12 = - 5x

After adding both sides by 12, the results is $\boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }$

<u>Alternative steps </u>

Substitutes m = -5 and (0, 12) to slope-intercept form $\boxed{ \ y = mx + c \ }$

12 = -5(0) + c

Constant c is 12 then arrange the slope-intercept form.

Similar results as above, i.e. $\boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }$

$\boxed{Standard \ form: ax + by = c, with \ a > 0}$

$\boxed{Point-slope \ form: y - y_1 = m(x - x_1)}$

$\boxed{Slope-intercept \ form: y = mx + k}$

<h3>Learn more </h3>

A similar problem brainly.com/question/10704388
Investigate the relationship between two lines brainly.com/question/3238013
Write the line equation from the graph brainly.com/question/2564656

Keywords: given line, the equation, slope-intercept form, standard form, point-slope, gradien, parallel, perpendicular, passes, through the point, constant

7 0

3 years ago

Read 2 more answers

Kayle and Olivia both just got their first jobs. After working for two weeks they received pay checks. Kayle received her check

MaRussiya [10]

Answer:

ovlivia makes more per hour than kayle

Step-by-step explanation:

ovlivia makes $8.75 per hour while Kayle makes $8.5 per hour

6 0

3 years ago

All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weigh

BaLLatris [955]

Answer:

The largest possible weight of flour is 11.25 pounds.

Step-by-step explanation:

To start with, we will assume that the weight of 1 sack of sugar = x pounds

We will also assume that the weight of 1 sack of flour = y pounds

So, the weight of 2 sacks of sugar = 2 * (x) = 2x

Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y

Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds

= 2x + 3y ≤ 40............ we'll call that equation 1.

Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds

= y ≤ 2x + 5........................ we'll call that equation 2

Therefore, we'll solve for the values of x and y in the two equations and we will get:

2x + 3y ≤ 40

y ≤ 2x + 5

Now, substitute the value of y into equation 1

2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40

⇒ 2x + 6x + 15= 40

⇒ 8x + 15 = 40

⇒ 8x = 25

⇒ x = 25/8

⇒ x = 3.12

x cannot be more than 3.12 pounds, so we solve for y

Putting the value of x into equation 2, we'll get

⇒ 2y + 5 = 2(3.12) + 5

⇒ y = 11.25 pounds.

So, n cannot be more than 11.25 pounds

8 0

3 years ago

The zeros for f(x)=x^4-4x^3-9x^2+36x are

Mrrafil [7]

X^4 - 4x^3 - 9x^2 + 36x = 0
x(x^3 - 4x^2 - 9x + 36) = 0
x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0

the zeroes are -3, 0, 3, 4 Answer

3 0

3 years ago

Solve for x when 4x+16/12=x-4

stira [4]

Answer:

In short, Your Answer would be either 1 or 7

Step-by-step explanation:

|4x + 12| = 16

As it is in modulus function, it could be either +ve or -ve

4x+12 = 16 OR 4x - 12 = 16

4x = 16-12 OR 4x = 16 + 12

4x = 4 OR 4x = 28

x = 4/4 OR x = 28/4

8 0

2 years ago