Answer:
-x^2 - 11x -30
Step-by-step explanation:
Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.
ie: x(x) and x(6)
ie: x^2 + 6x
Then do the 5 times the things in the second parenthesis.
ie: 5(x) and 5(6)
ie: 5x + 30
Then add what you got from multiplying the first value to what you got from multiplying the second.
ie: x^2 + 11x + 30
This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.
ie: -x^2 - 11x -30
Option C:
x = 30
Solution:
The given image is a triangle.
angle 1, angle 2 and angle 3 are interior angles of a triangle.
angle 4 is the exterior angle of a triangle.
m∠4 = 2x°, , m∠3 = 20°
Exterior angle theorem:
<em>In triangle, the measure of exterior angle is equal to the sum of the opposite interior angles.</em>
By this theorem,
m∠4 = m∠2 + m∠3
Subtract on both sides of the equation.
To make the denominator same and then subtract.
Multiply by on both sides of the equation.
x° = 30°
x = 30
Hence option C is the correct answer.
Question:
The options are;
A. The distances in the Olympic final were farther on average.
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
C. The distances in the Olympic final were all greater than the US qualifier distances
D. none of the above
Answer:
The correct option is;
A. The distances in the Olympic final were farther on average.
Step-by-step explanation:
From the options given, we have
A. The distances in the Olympic final were farther on average.
This is true as the sum of the 5 points divided by 5 is more in the Olympic final
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier
C. The distances in the Olympic final were all greater than the US qualifier distances
This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final
D. none of the above
We have seen a possible correct option in option A
Answer:
rpi^2 or pir^2
Step-by-step explanation:
radius times pi to the second