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Mars2501 [29]
3 years ago
5

A bungee jumper has a mass of 60kg and uses a 25m long bungee cord (unstretched length) with an elastic coefficient of 800N/m. a

) What is the maximum speed of the jumper? b) What is the maximum amount of stretch that will occur when the jumper drops from rest from a very high bridge?
Physics
2 answers:
belka [17]3 years ago
6 0

Answer:

a)

maximum speed of jumper is 22.14m/s

b)

Maximum stretch that will occur,x=94.3 m

Explanation:

Answer:

Explanation:

In this question we have given

mass of bungee jumper,m=60kg

length of cord,h=25m

elastic coefficient, k=800N/m

We have to find the maximum speed of the jumper

here law of conservation will be applied it means the potential energy lost by bungee jumper when he reaches at a specific depth is equal to the sum of strain energy which is produced due to stretching of bungee cord and kinetic energy gained.

It means

U=KE+SE....................(a)

Here potential energy of bungee jumper,U=mgh..................(1)

Put values of m,g and h in equation 1

we got,

U=60kg\times 9.8ms^{-2}\times25m

U=14700 J...........(2)

kinetic energy is given as

KE=\frac{mv^2}{2}..............(3)

put value of m in equation 3

KE=\frac{60v^2}{2}

KE=30v^2.............(4)

Strain energy is given as

SE=0 (when bungee cord is unscratched)

put values of KE and U in equation a we got

30v^2=14700\\v=22.14 ms^{-1}

maximum speed of jumper is 22.14m/s

b)

maximum amount of stretch be x

than SE=k(x-25)

put valuse of U,KE and SE in equation a

60\times 9.8\times (x+25)=\frac{30\times 22.14^2}{2}+800(x-25)\\588x+14700=14700+800x-20000\\212x=20000\\\\x=94.3 m

Maximum stretch that will occur,x=94.3 m

KonstantinChe [14]3 years ago
3 0

Answer:

a ) 2.68 m / s

b )  1.47 m

Explanation:

The jumper will go down with acceleration as long as net force on it becomes zero . Net force of (mg - kx ) will act on it  where kx is the restoring force acting in upward direction.

At the time of equilibrium

mg - kx = 0

x = mg / k

= (60 x 9.8 ) / 800

= 0.735 m

At this moment , let its velocity be equal to V

Applying conservation of energy

kinetic energy of jumper + elastic energy of cord = loss of potential energy of the jumper

1/2 m V² + 1/2 k x² = mg x

.5 x 60 x V² + .5 x 800 x .735 x .735 = 60 x 9.8 x .735

30 V² + 216.09 = 432.18

V = 2.68 m / s

b ) At lowest point , kinetic energy is zero and loss of potential energy will be equal to stored elastic energy.

1/2 k x² = mgx

x = 2 m g / k

= (2 x 60 x 9.8) / 800

= 1.47 m

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In order to solve the circuit, we first have to find the equivalent resistance of the whole circuit, then the total current, and then we can proceed finding the current and the voltage for each resistor.

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V_1=I_1 R_1=(3.98)(1.0)=3.98 V

This means that the voltage across resistor 6 is

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The voltage across resistor 5 is

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The current through resistor 4 is

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