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Bond [772]
3 years ago
8

A net force acting on a 5.0 kg box produces an acceleration of 4.2 m/s2. What acceleration, to the nearest tenth of a m/s2, will

the same net force cause on a 2.8 kg box
Physics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

The acceleration that the net force will cause is 7.5 m/s²

To solve this problem, first, we need to find the net force.

⇒ Equation:

F = ma................ Equation 1

⇒ Where:

  • m = mass of the box
  • a = acceleration of the box

From the question,

⇒ Given;

  • m = 5.0 kg
  • a = 4.2 m/s²

⇒ Substitute these values into equation 1

  • F = 5×4.2
  • F = 21 N

We also use the same equation 1 to find the acceleration that the net force will cause to a box of mass 2.8 kg.

⇒ make a the subject in equation 1

  • a = F/m................. Equation 2

⇒ Substitute the appropriate values into equation 2

  • a = 21/2.8
  • a = 7.5 m/s²

Hence, The acceleration that the net force will cause is 7.5 m/s²

Learn more about acceleration here: brainly.com/question/605631

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Answer:

225 rpm

Explanation:

The angular acceleration of the fan is given by:

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For the fan in this problem,

\omega_i = 0\\\omega_f = 180 rpm\\\Delta t=4 s

Substituting,

\alpha = \frac{180-0}{4}=45 rpm/s

Now we can find the angular speed of the fan at the end of the 5th second, so after t = 5 s. It is given by:

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Substituting,

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Using

Period ( P) is given as

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a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds

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