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Bad White [126]
4 years ago
12

1. During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the tre

buchet launches the stones with a velocity of +40.0 m/s at an angle of 55.0°, how long does it take the stone to hit the ground? What is the maximum distance that the trebuchet can be from the castle wall to be in range? How high will the stones go? Show all your work.
Physics
1 answer:
Grace [21]4 years ago
8 0
Initial velocity u = 40 
Angle at launch = 55 degrees
 At maximum height v = 0, velocity equation v^2 = u^2 - 2gh,
 0 = (40 x sin55)^2 - 2 x 9.81 x h => (40 x 0.819)^2 = 19.62h => h = 32.76^2 /
19.62
 Maximum height = 54.7 m 
 We have v = u - gt => 0 = (40 x sin55) - 9.81 x t => t = 32.76 / 9.81 => t =
3.34 s
 Time taken to hit the ground is 2t = 2 x 3.34 = 6.68 s 
Distance from castle to trebuchet = utcos55 = 40 x 6.68 x 0.573 = 153.1 m
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4 years ago
The quark composition of the proton and neutron are, respectively, uud and udd, where u is an up quark (charge +23e) and d is a
ludmilkaskok [199]

Answer:

Option C=> π+.

Explanation:

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8 0
3 years ago
Waves from a radio station have a wavelength of 369 m. They travel by two paths to a home receiver 20.0 km from the transmitter.
Olenka [21]

Answer:

92.25m

Explanation:

In order to solve the exercise, it is necessary to apply the concept of construtive interference due to a path difference.

The formula is given by,

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

where,

n is the index of refraction of the medium in which the wave is traveling

\lambda = wavelenght

\delta = is the path difference

m = integer (0,1,2,3...)

Since in this case we are dealing with an atmospheric environment, where air is predominant, we approximate n to 1.

And since we need the reflected wave,

\delta = 2x

Where x is the distance in one direction without return.

The distance must correspond to the minimum therefore m = 0, so

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

\delta = ({0+\frac{1}{2})\frac{369}{1}

\delta = 184.5m

Then the minimum distance is:

x= \frac{delta}{2}

x = \frac{184.6}{2}

x = 92.25m

Therefore the minimum distance from the mountain to the receiver that produces destructive interference at the receiver is 92.25m

5 0
3 years ago
Which of the following statements are true of the horizontal motion of projectiles? List all that apply.a. A projectile does not
r-ruslan [8.4K]

Answer:

d. A projectile with a horizontal component of motion will have a constant horizontal velocity.

f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.

g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.

h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.

Explanation:

When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>

On the other hand, the horizontal displacement x of the projectile is mathematically expressed as:

x=V_{ox} t  

Where:  

V_{ox} is the projectile's horizontal component of the initial velocity  

t is the time the parabolic motion lasts

This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.

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5 0
4 years ago
What velocity will a freefalling object have after falling 80 meters
vovangra [49]

Answer:

129.96

At a Gravitational acceleration of 32.17405 ( which is the normal rate for a freefall) you will geta velocity of 129.96 and the time of fall will be 4.039 seconds from 80 meters.

Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

6 0
3 years ago
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