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fgiga [73]
3 years ago
6

Does air pressure increase or decrease with an increase in altitude is the rate of change constant

Physics
1 answer:
Sliva [168]3 years ago
7 0
<span> The </span>rate<span> of </span>pressure decreases with an increase in altitude<span> is not </span>constant<span>. Rather, </span>pressure decreases<span> rapidly near Earth's surface and more gradually at greater heights. </span>
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1-A train travels 100 km to reach town A in one hour and 15 min. The train stops at station A for 45 minutes. Then it travels 15
kirill [66]

Answer 1) : 62.5 km/hour is the average velocity of the train.

2) The final velocity of the car at the end of 75 m is 14.69 m/s

Explanation:

1) Displacement of the train = 100 km + 150 km = 250 km

Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours

Average velocity=\frac{Displacement}{time}=\frac{250 km}{4 hour}=62.5 km/h

62.5 km/hour is the average velocity of the train.

2) The acceleration of the car, a= 1.2 m/s^2

Distance covered by the car,s = 75 m

Initial velocity of the car ,v_i = 6 m/s

Final velocity of thre car ,v_f=?

Using third equation of motion:

v_{f}^2=v_{i}^2+2as=(6 m/s)^2+2\times 1.2 m/s\times 75 m=216 m^2/s^2

v_{f}=14.69 m/s

The final velocity of the car at the end of 75 m is 14.69 m/s

8 0
2 years ago
Par 1/2
BaLLatris [955]

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

4 0
2 years ago
If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?
ivann1987 [24]

Answer: s=d/t= 500/7.0=71.42 m/s

Explanation:

5 0
3 years ago
900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge
mariarad [96]

Answer:

100

Explanation:

mark me brainliest

7 0
3 years ago
A system initially has an internal energy U of 504 J. It undergoes a process during which it releases 111 J of heat energy to th
Likurg_2 [28]

Answer:

615 J

Explanation:

internal energy (U) = 504 J

heat lost (q) = 111 J = - 111 J (negative sign is because heat is lost)

work done = 222 J

what is the final energy in the system

total energy = final energy - initial energy

final energy = total energy + initial energy

where

initial energy = 504 J

total energy = 222 - 111 = 111 J

final energy = 504 + 111 = 615 J

6 0
2 years ago
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