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fgiga [73]
3 years ago
6

Does air pressure increase or decrease with an increase in altitude is the rate of change constant

Physics
1 answer:
Sliva [168]3 years ago
7 0
<span> The </span>rate<span> of </span>pressure decreases with an increase in altitude<span> is not </span>constant<span>. Rather, </span>pressure decreases<span> rapidly near Earth's surface and more gradually at greater heights. </span>
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A charged particle enters a uniform magnetic field B_vec with a velocity v_vec at right angles to the field.It moves in a circle
Finger [1]

Answer:

D. 10 T

Explanation:

When a particle is moving in a magnetic field, the magnetic force provides the centripetal force that keeps the particle in circular motion.

The cyclotron period (the period the particle takes to complete one orbit) can be found to be

T=\frac{2\pi m}{qB}

where

m is the mass of the particle

q is its charge

B is the magnetic field

As we see, the period is directly proportional to the mass of the particle.

In this problem, the second particle is ten times as massive as the first one:

m' = 10 m

while the speed is the same. So, the period of the second particle is

T'=\frac{2\pi m'}{qB}=\frac{2\pi (10m)}{qB}=10 \frac{2\pi m}{qB}=10 T

8 0
3 years ago
a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the we
andreev551 [17]

Explanation:

The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end.  The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.

Sum the torques about the wedge (it may help to draw a diagram first).  Take counterclockwise to be positive.

∑τ = Iα

W (0.25 m) − (100 N) (0.50 m) = 0

W = 200 N

Sum the forces in the y direction.

∑F = ma

F − 100 N − 200 N = 0

F = 300 N

8 0
3 years ago
HURRY!!! I only have 14 more minutes
DochEvi [55]

Answer:

B-cells

T-cells

stem cells

Im like 95% sure good luck

Explanation:

I passed biology and science

8 0
3 years ago
Read 2 more answers
a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calc
kipiarov [429]
A. 0.5 miles an hour 
B. 0.2 miles an hour
4 0
3 years ago
How many joules of heat are needed to raise the temperature of 50.0 g of aluminum from 10°C to 110°C, if the specific heat of al
dusya [7]

Answer:

Heat required to raise the temperature of the aluminium is 4750 J

Explanation:

As we know that the heat energy required to raise the temperature of the aluminium is given as

Q = ms\Delta T

here we know that

m = 50 g

\Delta T = 110 - 10

\Delta T = 100 ^oC

so we have

Q = 50(0.95)(100)

Q = 4750 J

5 0
3 years ago
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