Answer:
1. a) 0.5 h = 1,800 s
h) 20 cm = 0.2 m
b) 2.0 h = 7,200 s
i) 5.0 kg = 5,000 g
c) 3.5 h = 12,600 s
j) 1.5 kg = 1,500 g
d) 1/4 h = 900 s
k) 450.0 g = 0.45 kg
e) 3.0 m = 300 cm
l) 20.0 g = 0.02 kg
f) 2.5 m = 250 cm
m) 500.0 g = 0.5 kg
g) 0.5 m = 500 mm
n) 1000.0 g = 1 kg
Answer:
The time where the avergae speed equals the instaneous speed is T/2
Explanation:
The velocity of the car is:
v(t) = v0 + at
Where v0 is the initial speed and a is the constant acceleration.
Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:
v_ave = v0+a(T/2)
We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>
v(T/2)=v_ave
Now we want to know where the car should be, the osition of the car is:
Where x_A is the position of point A. Therefore, the car will be at:
<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>