Answer:
C. 233 km/h
Explanation:
Ground speed = air speed + wind speed
250 km/h = v + 17 km/h
v = 233 km/h
Momentum = mass * velocity
p = mv
p = 1.5 kg * 40 ms^-1
p = 60 kgm/s
To find components of a vector:
px = p * cos(theta)
px = 60 * cos(30)
px = 51.96 = 52 (rounded to two significant digits)
py = p * sin(theta)
py = 60 * sin(30)
py = 30
He initial momentum is 60kgm/s
The horizontal component is 52 kgm/s
The vertical component is 30 kgm/s
Answer:
6 m/s
Explanation:
Given that :
mass of the block m = 200.0 g = 200 × 10⁻³ kg
the horizontal spring constant k = 4500.0 N/m
position of the block (distance x) = 4.00 cm = 0.04 m
To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.
i.e 
v = 6 m/s
Hence,the speed the block will be traveling when it leaves the spring is 6 m/s
Answer:because the parachute is built so the wind will push up on it make the man/woman glide or fall slowly will a stone which has a lot of desentity
falls through the air faster do to is weight and shape .
Explanation:
