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Rashid [163]
3 years ago
13

What radiation do remote controls use?

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:infrared radiation

Explanation:

Most remote control uses infrared radiation

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A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane
umka2103 [35]

Answer:

466 km/h

255°

measured anticlockwise from the east direction

Explanation:

find the resultant velocity of a plane after a crosswind affects its motion. take the positive

x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are

  • <em>upx =</em> 0
  • <em>upy =  450 Km/ h</em>

<em>And for the wind.</em>

  • <em>uwx = - 120 Km/h</em>
  • <em>uwy = 0</em>

<em>The components for the r</em><em>esultant velocity </em><em>of the plane are given by</em>

  • <em>ux =upx + uwx = 0 - 120 Km/h =  </em><u><em>- 120 Km/h</em></u>
  • <em>uy = upy + uwy  = - 450 Km/h +0 = </em><u><em>- 450 Km/h</em></u>

<em>The </em><em>magnitude </em><em>of the resultant velocity is</em>

<em />\sqrt{(vx)^2+(vy)^2} =\sqrt{(-120lkm/h^2+(-450lkm/h)^2}

= 466 km/h

Hope this helps u : )

7 0
1 year ago
Lightsail-2 is a spacecraft launched in June 2019 by the Planetary Society driven by radiation pressure on a solar sail of area
lozanna [386]

Answer:

2.655\times 10^{13}\ photons

Explanation:

Area of the solar sail = A = 30 m2

Solar constant = I = 1388 W/m2

Planck's constant = h = 6.626 × 10⁻³⁴ m²kg/s

Speed of light = c = 3×10⁸ m/s

Wavelength of light = \lambda = 570 nm

Pressure from radiation

P=2\frac{I}{c}\\\Rightarrow P=2\frac{1388}{3\times 10^8}\\\Rightarrow P=9.253\times 10^{-6}\ W

Energy of a photon

E=\frac{hc}{\lambda}\\\Rightarrow E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{570\times 10^{-9}}\\\Rightarrow E=3.487\times 10^{-19}\ J

Number of photons

n=\frac{P}{E}\\\Rightarrow n=\frac{9.253\times 10^{-6}}{3.487\times 10^{-19}}\\\Rightarrow n=2.655\times 10^{13}\ photons

Number of photons is 2.655\times 10^{13}\ photons

3 0
3 years ago
Will a beam of light that is, at first, in air and oriented perpendicular to the surface of a body of water be deflected as a re
EastWind [94]

When a beam of light  that is, at first, in air and oriented perpendicular to the surface of a body of water be deflected as a result of transition into water--------It does not deflect , the light direction will not change.

What happens to light when it passes through air?

All materials have what is known as an index of refraction, which is linked to how fast light can travel through the material. As light passes through air and into another clear material (such as glass), it changes speed, and light is both reflected and refracted by the glass.

How does light travel through air and water?

When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.

Learn more about direction of beam of light:

brainly.com/question/31869803

#SPJ4

4 0
2 years ago
A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potent
vfiekz [6]

The potential difference comes out to be

10 \times 10 {}^{ - 3} m

Given:

σ = 8. 85 × 10-9 c/m2

we know,

E = \frac{σ}{2ε0}

E =  \frac{8.85 \times 10 {}^{ - 9} }{2ε0}

E =  \frac{v}{d}

given the potential difference between two equipotential surface=5v

E=∆v

∆d=∆v/E

=  \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} }

Δ = 10 \times 10 {}^{ - 3} m

Thus the potential difference is

10 \times 10 {}^{ - 3} m

Learn more about potential difference from here: brainly.com/question/28165869

#SPJ4

5 0
1 year ago
You throw a rock straight up into the air with a speed of 14.2 m/s. how long does it take the rock to reach its highest point?
slega [8]

The acceleration of gravity on or near the Earth's surface is 9.8 m/s² downward.
Is that right ?           I don't hear any objection, so I'll assume that it is.

That means that during every second that gravity is the only force on an object,
the object either gains 9.8m/s of downward speed, or it loses 9.8m/s of upward
speed.   (The same thing.)

If the rock starts out going up at 14.2 m/s, and loses 9.8 m/s of upward speed
every second, it runs out of upward gas in (14.2/9.8) = <em>1.449 seconds</em> (rounded)

At that point, since it has no more upward speed, it can't go any higher.  Right ?

(crickets . . .)

4 0
3 years ago
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