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Vsevolod [243]
2 years ago
11

Tell me the answer please

Physics
2 answers:
beks73 [17]2 years ago
8 0

Answer: transverse, ripples formed on the surface of water

Explanation:

It is transverse

Examples are ripples formed on the surface of water

STatiana [176]2 years ago
7 0

Answer:

transverse wave is the answer

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A tank of water is in the shape of a cone (assume the ""point"" of the cone is pointing downwards) and is leaking water at a rat
Inessa05 [86]

Answer:

a) dh/dt = -44.56*10⁻⁴ cm/s

b) dr/dt = -17.82*10⁻⁴ cm/s

Explanation:

Given:

Q = dV/dt = -35 cm³/s

R = 1.00 m

H = 2.50 m

if h = 125 cm

a) dh/dt = ?

b) dr/dt = ?

We know that

V = π*r²*h/3

and

tan ∅ = H/R = 2.5m / 1m = 2.5  ⇒ h/r = 2.5

⇒  h = (5/2)*r

⇒  r = (2/5)*h

If we apply

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒  d(r²*h)/dt = 3*35/π = 105/π   ⇒   d(r²*h)/dt = -105/π

a) if   r = (2/5)*h

⇒  d(r²*h)/dt = d(((2/5)*h)²*h)/dt = (4/25)*d(h³)/dt = -105/π

⇒  (4/25)(3*h²)(dh/dt) = -105/π

⇒  dh/dt = -875/(4π*h²)

b) if  h = (5/2)*r

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒  d(r²*h)/dt = d(r²*(5/2)*r)/dt = (5/2)*d(r³)/dt = -105/π

⇒  (5/2)*(3*r²)(dr/dt) = -105/π

⇒  dr/dt = -14/(π*r²)

Now, using h = 125 cm

dh/dt = -875/(4π*h²) = -875/(4π*(125)²)

⇒  dh/dt = -44.56*10⁻⁴ cm/s

then

h = 125 cm  ⇒  r = (2/5)*h = (2/5)*(125 cm)

⇒  r = 50 cm

⇒  dr/dt = -14/(π*r²) = - 14/(π*(50)²)

⇒  dr/dt = -17.82*10⁻⁴ cm/s

4 0
3 years ago
Helppppo please help help I have no time quick I’m in the exam
Sunny_sXe [5.5K]

Answer:

D

Explanation:

calculate effective resistance of the resistors

= 80 + 120

= 200

overall resistance = 48 ohms

so overall current flowing through circuit

I = V / R

I = 12 / 200

I = 0.06 A

since circuit is in series, current is same at every point so...

potential difference across 80 = R x I

= 80 x 0.06

answer is potential difference = 4.8 V

hope this helps

please mark it brainliest

I just learned this chapter recently

5 0
3 years ago
A particle undergoes two displacements. The first has a
Novay_Z [31]
First you need to draw the picture of the problem to better understand it. Like the one bellow. 

In this task you have 2 sides of triangle and we can calculate angle between them. Angle between them is 120 - 35 = 85 degrees.

Once you have those 3 variables you can calculate third side of triangle using cosine law.
a - second displacement
b - first displacement
c- resultant displacement.

a^{2} =  b^{2}+ c^{2}-2*b*c*cos85
now we just need to calculate this.
a^{2} = 38439.458
a = 196

now, we use cosine law again to find the angle between second and first displacement.
\alpha = 45.36 degrees

The angle marked with "?" in the graph is our direction angle. We will call it \beta

\beta =90-30-45.36 = 14.64

Second displacement has magnitude of 196 and a direction of -14.64 with positive x axis
3 0
3 years ago
Please help on this one?
vlada-n [284]

Answer:

idk

Explanation:

7 0
3 years ago
The sun's electromagnetic radiation is produced by
Hoochie [10]
The Sun emits electromagnetic radiation at many wavelengths across the EM spectrum.
5 0
3 years ago
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