I would do a windmill project!
Hope it helps!:)
Answer:
Explanation: someone help me please you want free points right
Answer:
The initial velocity of the ball is 28.714 m/s
Explanation:
Given;
time of flight of the ball, t = 2.93 s
acceleration due to gravity, g = 9.8 m/s²
initial velocity of the ball, u = ?
The initial velocity of the ball is given by;
v = u + (-g)t
where;
v is the final speed of the ball at the given time, = 0
g is negative because of upward motion
0 = u -gt
u = gt
u = (9.8 x 2.93)
u = 28.714 m/s
Therefore, the initial velocity of the ball is 28.714 m/s
By definition we have to:
LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
Where,
k1 = 0.0117 s-1
K2 = 0.689 s-1
T1 = 400.0 k
T2 = 450.0 k
R is the ideal gas constant
R = 8.314 KJ / (Kmol * K)
Substituting
ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
Clearing Ea:
Ea = 122 kJ
answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
Answer:
B
Explanation:
Let m be mass of the object and v be speed of object b.
Kinetic Energy of B = 1/2 mv^2
Kinetic Energy of A = 1/2 m(2v)^2
= 2 mv^2
= 4 (1/2 mv^2)
= 4 × Kinetic Energy of B
Hence Object A has four times the kinetic energy of object B (<em>A</em><em>n</em><em>s</em><em> </em><em>B</em><em>)</em>
