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geniusboy [140]

2 years ago

13

A driver traveled 270 km in 3 hours. The driver’s destination was still 150 km away. What was the driver’s average speed at this

point?

1 answer:

evablogger [386]2 years ago

6 0

The driver was going 90 kilometers every hour.

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A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark

Natali5045456 [20]

The total displacement of the toy car at the given positions is 0.

The given parameters;

<em>First displacement of the car, = 5 cm left</em>
<em>Second displacement of the car, = 8 cm right</em>
<em>Third displacement of the car, = 3 cm to the left</em>

The total displacement of the car is calculated as follows;

<em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
<em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

$\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0$

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

6 0

2 years ago

Read 2 more answers

A ball is dropped from a window and takes two seconds to reach the ground .it starts from rest and reaches a final speed of 20m/

Akimi4 [234]

The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .

If an object starts from rest and its speed after 2 seconds is 20 m/s, then its acceleration is 20/2 = 10 m/s^2 .

(Gravity on Earth is only 9.8 m/s^2.)

3 0

2 years ago

Consider two ideal gases, A & B, at the same temperature. The rms speed of the molecules of gas A is twice that of gas B. Ho

uysha [10]

Answer:

option (d)

Explanation:

The relation between the rms velocity and the molecular mass is given by

v proportional to \frac{1}{\sqrt{M}} keeping the temperature constant

So for two gases

$\frac{v_{A}}{v_{B}}=\sqrt{\frac{M_{B}}{M_{A}}}$

$\frac{2v_{B}}{v_{B}}=\sqrt{\frac{M_{B}}{M_{A}}}$

${\frac{M_{B}}{M_{A}}} = 4$

${\frac{M_{B}}{4}} = M_{A}$

7 0

3 years ago

Answer and explanation please!!

expeople1 [14]

Answer:

Option 3

Explanation:

O Option C is NEGATIVELY CHARGED, meaning it has GAINED ELECTRONS resulting in a GREATER number of ELECTRONS than PROTONS.

8 0

2 years ago

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If the current in a wire increases from 5 A to 10 A, what happens to its magnetic field? If the distance of a charged particle f

Anna007 [38]

(1) Doubling of the current through the wire will result in doubling of its magnetic field.

The magnetic field around a wire is a function of the current I and radial distance r

$B = \frac{\mu\cdot I }{2\pi r}$

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A

(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.

(3) Answer

If a particle with a charge q moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

$F_m = B\cdot v\cdot q$

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC

3 0

2 years ago

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