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zaharov [31]
3 years ago
7

Given r(x) = StartFraction 11 Over (x minus 4) squared EndFraction , which represents a domain restriction on r(x) and the corre

sponding inverse function?

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Answer for edgenuity

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Solve for z<br><br> Z - 4/9 - 1/3 = 5/9
Aleks04 [339]

Answer:

4/3

Step-by-step explanation:

<em>Z-</em><em>4</em><em>/</em><em>9</em><em>-</em><em>1</em><em>/</em><em>3</em><em>=</em><em>5</em><em>/</em><em>9</em>

<em>Z-</em><em>7</em><em>/</em><em>9</em><em>=</em><em>5</em><em>/</em><em>9</em>

<em>Z</em><em>=</em><em>5</em><em>/</em><em>9</em><em>+</em><em>7</em><em>/</em><em>9</em><em> </em>

<em>Z</em><em>=</em><em>4</em><em>/</em><em>3</em><em> </em><em>not</em><em> </em><em>sure</em><em> </em><em />

3 0
3 years ago
HELPPPPPPPPP PLEASEEEEEEEE
Natalija [7]

B C are parellagrams the other are NOT

8 0
2 years ago
Simplify equation: 6x2+7x−3x2−2x
tigry1 [53]

Answer:

8x+4

Step-by-step explanation:

5 0
3 years ago
What is the difference of the polynomials? (m^2n^2-7)-(mn+4)
Vilka [71]

Answer: The difference is,

m^2n^2-mn-11

Step-by-step explanation:

Given expression is,

(m^2n^2-7)-(mn+4)

By distributive property,

m^2n^2-7-mn-4

Combine like terms( that have the same variables and powers ),

m^2n^2-mn-11

Which is the required result.

Hence, option third is correct.

4 0
3 years ago
Two cross roads, each of width Sm, run at right angles through the
Ray Of Light [21]

Answer:

Rs 57750

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

7 0
3 years ago
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