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Mariulka [41]
3 years ago
8

Convert 5.8 km to the unit mm. 0.0000058 mm 0.0058 mm 5,800 mm 5,800,000 mm

Chemistry
1 answer:
spin [16.1K]3 years ago
5 0
Its going to b 5,800,000 due to each Km being 1,000,000 Mm
Hope this helps :D
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4 years ago
If 45.0 mL of 6.00M HCl is added to 130 mL of H2O, Determine the molarity of the final solution. (show work)
Ivahew [28]

2.07 M is the molarity of the final solution if 45.0 ml of 6.00M HCl is added to 130 ml of H_{2}O.

Explanation:

Data given:

volume of HCl, V1 = 45 ml

molarity of the HCl solution, M1 = 6 M

final volume of the HCl solution after water is added, V2 = 130 ml

final molarity M2 =?

After the dilution, the molarity of the new solution can be found by using the formula:

M1V1 = M2V2

here M1 and V1 are the molarity and volume for concentrated solution, M2 and V2 represents the diluted solution's molarity and volume.

Applying the formula after rearranging the equation, we get

M2 = \frac{M1V1}{V2}

M2 = \frac{6X45}{130}

M2 = 2.07 M

The final molarity of the HCl solution is 2.07 M

4 0
4 years ago
The half-life of the radioisotope 158Eu is 0.77 h. How much time is required for a 160.0-g sample of 158Eu to decay to 2.07 g?
Grace [21]

Answer: e. 4.8 h

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

a) for rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{0.77hr}=0.9hr^{-1}

b) for 160.0 g to decay to 2.07 g

t=\frac{2.303}{0.9}\log\frac{160.0}{2.07}

t=4.8hr

The time  required for a 160.0-g sample of 158Eu to decay to 2.07 g is 4.8 hours

7 0
3 years ago
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