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2 years ago

Calculate the maximum concentration (in M) of calcium ions (Ca2+) in a solution that

Chemistry

1 answer:

Vilka [71]2 years ago

4 0

The maximum concentration of calcium ions (Ca₂+) in a solution that

contains CO₃ will be 6.18 × 10⁻⁸. The correct option is D).

<h3>What is concentration?</h3>

The concentration of any substance is the presence or the amount of that substance in a specific place. It is also called the molar mass of the substance.

Ksp is the solubility equilibrium of a substance when it remains in its solid state.

The chemical equation will be

CaCO₃ ⇌Ca²⁺+CO₃²⁻

Ksp = [Ca²⁺][CO₃²⁻]

given Ksp = 3.4 × 10⁻⁹ [CO₃²⁻] = 0.055M

[Ca²⁺] = Ksp / [CO₃²⁻] 3.4×10⁻⁹ / 0.055 = 6.18 × 10⁻⁸

Thus, the Ksp of CaCO₃ = 6.18 × 10⁻⁸. The correct option is D).

To learn more about concentration, refer to the link:

brainly.com/question/17102479

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What is the volume of a balloon if it contains 3.2 moles of helium at a temperature of 20. °C and standard pressure?

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1.14 mol

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3 years ago

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction

11Alexandr11 [23.1K]

Answer:

Balanced equation:

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

$Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate$

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Ionic equation:

$Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}$

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

$Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)$

4 0

3 years ago

How many molecules in each sample? 64.7 g N2 83 g CCl4 19 g C6H12O6

lilavasa [31]

Answer:

1.39x10²⁴ molecules N₂

.25x10²³ molecules CCl₄

6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we convert the given masses into moles, using the compounds' respective molar mass:

64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂

83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄

19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by Avogadro's number, to calculate the number of molecules:

2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules

0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules

0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules

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2 years ago

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3 years ago

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Calculate the amount of energy required to melt 500 g of ice at 0oc. (δhfus=5.96 kj/mole; δhfus is the energy required to melt i

marta [7]

When you want to melt an ice, you only need the latent energy of fusion, δhfus. We use the given value, then multiply this with the given amount to determine the amount of energy. Since the energy is per mole basis, use the molar mass of ice which is 18 g/mol. The solution is as follows:

ΔH = 5.96 kJ/mol * 1 mol/18 g * 500 g
ΔH = 165.56 kJ

3 0

3 years ago