Evaluate the expression when x = 2, y = 3, and z = -4 3X-2

1. Convert the following temperatures to the celsius scale. (a) 293 K (b) 470 K.

finlep [7]

293k = 293- 273

= 20°C

5 0

3 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

Given: Quadrilaterals ABCD ~ EFGH , with measure of angle A = 47 degrees, measure of angle B = 39 degrees, and measure of angle

kaheart [24]

Answer:

The answer is below

Step-by-step explanation:

Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.

Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.

In quadrilateral ABCD:

∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)

Substituting:

47 + 39 + 112 + ∠D = 360

∠D + 198 = 360

∠D = 360 - 198

∠D = 162°

The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:

∠A = ∠E = 47°

∠B = ∠F = 39°

∠C = ∠G = 112°

∠D = ∠H = 162°

3 0

3 years ago

Solutions to x^=-11x+4

anastassius [24]

x=-11x+4

x+11x=-11x+4+11x

12x=4

x= 4/12

<h2>Answer: x=1/3</h2>

5 0

4 years ago

What proportion of a normal distribution corresponds to z scores greater than 1.04?

Tom [10]

We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.

The answer is 0.1492.

7 0

3 years ago

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