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Reika [66]
2 years ago
6

Which has more thermal energy, a 5-kg bowling all that has been resting on a hot driveway for 4 hours on a 350C day, or the same

bowling ball rolling down a lane in an air-conditioned bowling alley? Explain.
Physics
2 answers:
Leviafan [203]2 years ago
6 0

The bowling ball on the driveway has more thermal energy.  It has been absorbing the radiant energy from the sun during those four hours. It is gaining temperature because of getting heated up, In fact, it will burn your hands when you picked it up.  But the ball in second case it has kinetic energy which is different . At the bowling alley, the ball does gain a slight amount of heat from rolling, but it is not hot enough to hurt your hands.

balandron [24]2 years ago
4 0

Answer:

Case 1

Explanation:

Case 1: A 5-kg bowling ball that has been resting on a hot driveway for 4 hours on a 35°C day,

Case 2: A 5-kg bowling ball rolling down a lane in an air-conditioned bowling alley

The question asks which of the two cases above have a higher thermal energy.

Thermal energy refers to the internal energy of objects due to the kinetic energy of its atoms and/or molecules.

This means that there are greater thermal energy in the atoms or molecules of hot objects than cold objects

Using this illustration, we understand that the bowling ball in case 1 has been absorbing the radiant energy from the sun for four hours and apparently, it is hotter than the ball in case 2;

Conclusively, case 1 has a higher thermal energy than 2.

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observe the figure given carefully volume of water in each vessel is shown arrange them in order of decreasing pressure at the b
mihalych1998 [28]

Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

 P=Ro*g*h

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be  

The largest pressure with the largest height of the liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.  

The pressure decreases as we go from the container B - D - A - C

5 0
3 years ago
Convert the following in to SI units without changing its values<br> a. 4000 g <br>b. 2.4 km​
lana66690 [7]

hi <3

i believe i explained this answer properly in my last answer but it would be 4kg and 2400m as these are the SI units for these values.

hope this helps :)

3 0
3 years ago
Read 2 more answers
How many sides does a dodecahedron have?
Serhud [2]

Answer:

twelve facesFrom left to right the solids are tetrahedron (four sides), cube (six sides), octahedron (eight faces), dodecahedron (twelve faces), and icosahedron (twenty faces).

Explanation:

Ayo hope you enjoy

8 0
2 years ago
Read 2 more answers
Which of the following best defines insulator?
aliya0001 [1]

Answer:

A substance with low ability or no ability to conduct energy.

Such as Rubber,Silicone,Plastic

6 0
3 years ago
A 60 kg acrobat is in the middle of a 10 m long tightrope. The center of the rope dropped 30 cm in relation to the ends that are
Zigmanuir [339]

Answer:

The tension in each half of the rope, is approximately 4,908.8 N

Explanation:

The mass of the acrobat, m = 60 kg

The length of the rope, l = 10 m

The extent by which the center dropped = 30 cm = 0.3 m

Let, 'T' represent the tension in each half of the rope

Weight, W = Mass, m × The acceleration due to gravity, g

∴ W = m × g

The acceleration due to gravity, g ≈ 9.8 m/s²

∴ The weight of the acrobat, W = 60 kg × 9.8 m/s² ≈ 588 N

The angle the dropped rope makes with the horizontal, θ is given as follows;

θ = arctan((0.3 m)/(5 m)) = arctan(0.06) ≈ 3.434°

At equilibrium, the sum of vertical forces, \Sigma F_y = 0

The vertical component of the tension, T_y, in each half of the rope is given as follows;

T_y = T × sin(θ)

∴ \Sigma F_y = W + T × sin(θ) + T × sin(θ) = W + 2 × T × sin(θ)

Plugging in the values, with θ = arctan(0.06) for accuracy, we get;

588 N + 2 × T × sin(arctan(0.06) = 0

∴ 2 × -T × sin(arctan(0.06) = 588 N

-T= 588 N/(2 × sin(arctan(0.06)) = 4,908.81208 N ≈ 4,908.8 N

The tension in each half of the rope, T ≈ 4,908.8 N.

4 0
2 years ago
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