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Reika [66]
2 years ago
6

Which has more thermal energy, a 5-kg bowling all that has been resting on a hot driveway for 4 hours on a 350C day, or the same

bowling ball rolling down a lane in an air-conditioned bowling alley? Explain.
Physics
2 answers:
Leviafan [203]2 years ago
6 0

The bowling ball on the driveway has more thermal energy.  It has been absorbing the radiant energy from the sun during those four hours. It is gaining temperature because of getting heated up, In fact, it will burn your hands when you picked it up.  But the ball in second case it has kinetic energy which is different . At the bowling alley, the ball does gain a slight amount of heat from rolling, but it is not hot enough to hurt your hands.

balandron [24]2 years ago
4 0

Answer:

Case 1

Explanation:

Case 1: A 5-kg bowling ball that has been resting on a hot driveway for 4 hours on a 35°C day,

Case 2: A 5-kg bowling ball rolling down a lane in an air-conditioned bowling alley

The question asks which of the two cases above have a higher thermal energy.

Thermal energy refers to the internal energy of objects due to the kinetic energy of its atoms and/or molecules.

This means that there are greater thermal energy in the atoms or molecules of hot objects than cold objects

Using this illustration, we understand that the bowling ball in case 1 has been absorbing the radiant energy from the sun for four hours and apparently, it is hotter than the ball in case 2;

Conclusively, case 1 has a higher thermal energy than 2.

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Figure 1 shows a wave movement during one second. What is the frequency of the wave
Andreyy89
This is 2 hertz.  You can mark out 2 full wavelengths in the second of time.
4 0
3 years ago
Read 2 more answers
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
2 years ago
14. A rocket is shot up into the air and then comes back down and hits the ground 9.2 second later.
sineoko [7]

Answer:

105.8 m

46 m/s

Explanation:

From the time the rocket is launched to the time it reaches its maximum height:

v = 0 m/s

a = -10 m/s²

t = 9.2 s / 2 = 4.6 s

Find: Δy and v₀

Δy = vt − ½ at²

Δy = (0 m/s) (4.6 s) − ½ (-10 m/s²) (4.6 s)²

Δy = 105.8 m

v = at + v₀

0 m/s = (-10 m/s²) (4.6 s) + v₀

v₀ = 46 m/s

3 0
3 years ago
Q7:<br> A 4 kg toy is lifted off the ground and falls at 3 m/s. What is the toy's energy?
alexandr1967 [171]

Answer:

The toy's energy is 18 J.

Explanation:

We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.

The toy will have kinetic energy due to its motion. The energy is given by :

E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 4\times 3^2\\\\E=18\ J

So, the toy's energy is 18 J.

7 0
2 years ago
Help on matching please, struggling on it. Even just 1 or 2 would help
n200080 [17]

Answer:

7. free fall -- h. 9.8m/s^2

3. Velocity -- x. 60 km/hr west

6. Acceleration -- d. change in velocity/time

8. Centrifugal --  s. towards the centre

13. Work done --w. Force * displacement

5. Uniform circular motion --j. spin cycle in washer

18. Power -- r. kW an hour

7. g -- a. 10N

hope this helps

6 0
2 years ago
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