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Reika [66]
3 years ago
6

Which has more thermal energy, a 5-kg bowling all that has been resting on a hot driveway for 4 hours on a 350C day, or the same

bowling ball rolling down a lane in an air-conditioned bowling alley? Explain.
Physics
2 answers:
Leviafan [203]3 years ago
6 0

The bowling ball on the driveway has more thermal energy.  It has been absorbing the radiant energy from the sun during those four hours. It is gaining temperature because of getting heated up, In fact, it will burn your hands when you picked it up.  But the ball in second case it has kinetic energy which is different . At the bowling alley, the ball does gain a slight amount of heat from rolling, but it is not hot enough to hurt your hands.

balandron [24]3 years ago
4 0

Answer:

Case 1

Explanation:

Case 1: A 5-kg bowling ball that has been resting on a hot driveway for 4 hours on a 35°C day,

Case 2: A 5-kg bowling ball rolling down a lane in an air-conditioned bowling alley

The question asks which of the two cases above have a higher thermal energy.

Thermal energy refers to the internal energy of objects due to the kinetic energy of its atoms and/or molecules.

This means that there are greater thermal energy in the atoms or molecules of hot objects than cold objects

Using this illustration, we understand that the bowling ball in case 1 has been absorbing the radiant energy from the sun for four hours and apparently, it is hotter than the ball in case 2;

Conclusively, case 1 has a higher thermal energy than 2.

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action and reaction are equal in magnitude and opposite in direction then why do they not balance each other.​
NeX [460]

Answer:

Newton’s third law of motion states that every action has an equal and opposite reaction. This indicates that forces always act in pairs. Reaction forces are equal and opposite, but they are not balanced forces because they act on different objects so they don’t cancel each other out.

7 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl
aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i:  unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R=  131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2}  }

D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2}  }

D₂= 167.21 cm

Direction of the second displacement

\beta = tan^{-1} \frac{D_{y}}{D_{x} }

\beta = tan^{-1} \frac{62.18}{155.22 }

β= 21.8°

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0
3 years ago
In what direction does an applied force move an object
mr Goodwill [35]
In the direction the force is directed towards. If the boy kicks the ball to the right, the ball will roll to the right.
4 0
3 years ago
Read 2 more answers
How does Ben and Jerry's total displacement compare to their distance traveled?
Sladkaya [172]

Answer:comparing the total displacement and tota distance covered by Ben Jerry.

Explanation:

Total distance travelled by both is;

m+n=z

Total displacement of both is;

x+y=z

Therefore;

comparing equation 1 and 2;

x+y=m+n

5 0
3 years ago
Two cars, one of mass 1300 kg, and the second of mass 2400 kg, are moving at right angles to each other when they collide and st
Margarita [4]

To solve this problem we will apply the momentum conservation theorem, that is, the initial momentum of the bodies must be the same final momentum of the bodies. The value that will be obtained will be a vector value of the final speed of which the magnitude will be found later. Our values are given as,

m_1 = 1300kg

m_2 = 2400kg

u_1 = 12m/s i

u_2 = 18m/s j

Using conservation of momentum,

m_1u_1+m_2u_2 = (m_1+m_2)v_f

1300*12i-2400*18j = (1300+2400)v_f

Solving for v_f

v_f = 4.2162i-11.6756j

Using the properties of vectors to find the magnitude we have,

|v| = \sqrt{(4.2162^2)+(-11.6756)^2}

|v| = 12.4135m/s

Therefore the magnitude of the velocity of the wreckage of the two cars immediately after the collision is 12.4135m/s

6 0
2 years ago
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