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4 years ago

8

A pail of water is rotated in a vertical circle of radius r = 1.6 m . The acceleration of gravity is 9.8 m/s 2 . r v What is the

minimum speed of the pail at the top of the circle if no water is to spill out? Answer in units of m/s.

1 answer:

Snowcat [4.5K]4 years ago

8 0

Answer:3.95 m/s

Explanation:

Given

radius of circle $r=1.6 m$

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e. $a_c\geq g$

$a_c=\frac{v^2}{r}$

$\frac{v^2}{r}\geq g$

$v_{min}=\sqrt{gr}$

$v_{min}=\sqrt{9.8\times 1.6}$

$v_{min}=\sqrt{15.68}$

$v_{min}=3.95 m/s$

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