Answer:
-20.158ft-lb
Explanation:
Check the attached files for the explanation.
Answer:
The velocity is 40 ft/sec.
Explanation:
Given that,
Force = 3200 lb
Angle = 30°
Speed = 64 ft/s
The resistive force with magnitude proportional to the square of the speed,

Where, k = 1 lb s²/ft²
We need to calculate the velocity
Using balance equation

Put the value into the formula

Put the value of k


At terminal velocity 
So, 


Hence, The velocity is 40 ft/sec.
Solution :
Speed of the air craft,
= 262 m/s
Fuel burns at the rate of,
= 3.92 kg/s
Rate at which the engine takes in air,
= 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft,
=921 m/s
Therefore, the upward thrust of the jet engine is given by

F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
= 
Therefore thrust of the jet engine is
.
Answer:
.2166 repeating or 21.66% repeating
Explanation:
In attached image
Since the tower base is square with a side length of 125 m,
Therefore,

Square root of 31250 = 176.776953 (Diameter)
, so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.
The volume of cylinder,

Thus, the mass of the air in the cylinder,

Hence, the mass of the air in the cylinder is this more than the mass of the tower.