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Evgen [1.6K]
3 years ago
15

S/REF No. Date If the load distance of a level is 20 cm and effort distance is 6ocm, calculate the amount of effort required to

lift a load 200 N.​
Physics
1 answer:
andrew11 [14]3 years ago
7 0
The answer is 602 cause I added
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An outfielder throws a baseball with an initial speed of 81.8mi/h. Just before an infielder catches the ball at the same level,
agasfer [191]

Answer:

-20.158ft-lb

Explanation:

Check the attached files for the explanation.

3 0
3 years ago
A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exe
Karolina [17]

Answer:

The velocity is 40 ft/sec.

Explanation:

Given that,

Force = 3200 lb

Angle = 30°

Speed = 64 ft/s

The resistive force with magnitude proportional to the square of the speed,

F_{r}=kv^2

Where, k = 1 lb s²/ft²

We need to calculate the velocity

Using balance equation

F\sin\theta-F_{r}=m\dfrac{d^2v}{dt^2}

Put the value into the formula

3200\sin 30-kv^2=m\dfrac{d^2v}{dt^2}

Put the value of k

3200\times\dfrac{1}{2}-v^2=m\dfrac{d^2v}{dt^2}

1600-v^2=m\dfrac{d^2v}{dt^2}

At terminal velocity \dfrac{d^2v}{dt^2}=0

So, 1600-v^2=0

v=\sqrt{1600}

v=40\ ft/sec

Hence, The velocity is 40 ft/sec.

4 0
3 years ago
A jet aircraft is traveling at 262 m/s in hor-
NeTakaya

Solution :

Speed of the air craft, $S_a$ = 262 m/s

Fuel burns at the rate of, $S_b$ = 3.92 kg/s

Rate at which the engine takes in air, $S_{air}$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft, $S_{exh}$ =921 m/s

Therefore, the upward thrust of the jet engine is given by

$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$

F = 85.9(921 - 262) + (3.92 x 921)

   = 4862635.79 + 3610.32

   = $4.8 \times 10^6 \ N$

Therefore thrust of the jet engine is $4.8 \times 10^6 \ N$.

3 0
2 years ago
An engine takes in 2400 J of heat, and rejects 1880 J of heat into the air. What is the efficiency of the engine? (No Unit)
Galina-37 [17]

Answer:

.2166 repeating or 21.66% repeating

Explanation:

In attached image

8 0
3 years ago
The eiffel tower has a mass of 7.3 million kilograms and a height of 324 meters. its base is square with a side length of 125 me
uranmaximum [27]

Since the tower base is square with a side length of  125 m,

Therefore,

(125\ m)^2+ (125\ m)^2=31250 m^2

Square root of 31250 = 176.776953 (Diameter) , so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.

The volume of cylinder,

=\pi r^2h=3.14(88.38834765 m)^2\times 324 m =7948168.803\ m^3

Thus, the mass of the air in the cylinder,

=1.225\ kg/m^3 \times 7948168.803\ m^3=9736506.78\ kg

Hence, the mass of the air in the cylinder is this more  than the mass of the tower.


4 0
3 years ago
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