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4 years ago

Let log p/n=6 and log m/n=8 what is the relationship between p and m?

Mathematics

2 answers:

madam [21]4 years ago

8 0

The answer is m=100p on apex

Mrac [35]4 years ago

6 0

By the laws of logs
log p/n = log p - log n = 6
log m/n = log m - log n = 8 subtract

log m - log p = 2

log m/p = 2

So m / p = 100

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Margaret has $200 in her savings account. She will save $50 more dollars each week and not take any money out of the account. Wh

Ad libitum [116K]

Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had

4 0

3 years ago

Four times one number minus three times another number is 12. Two times the first number added to three times to the second numb

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

x = first number, y = second number

4x - 3y = 12

2x + 3y = 6

------------------add

6x = 18

x = 18/6

x = 3

4x - 3y = 12

4(3) - 3y = 12

12 - 3y = 12

-3y = 12 - 12

-3y = 0

y = 0

solution : (3,0)

4 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Write 12/32 in simplest

kherson [118]

Step-by-step explanation:

12/32 in simplest form

First both have the table of 4 in common

3/8

Then we cannot divide it further so this is the simplest form

7 0

3 years ago

Rewrite the equation by completing the square. 4 x^{2} -12 x +9 = 04x 2 −12x+9=0

DedPeter [7]

Answer:

(2x -3)^2 = 0

Step-by-step explanation:

In this particular instance, the square is already complete. The rewrite is to show that.

(2x -3)^2 = 0

In the general case, ...

(ax +b)^2 = a^2x^2 +2abx +b^2

Comparing this form to the given left-side expression, we see that ...

a = 2, b = -3

So, the trinomial is already a perfect square trinomial.

4 0

3 years ago

Please answer both questions math

djyliett [7]

Answer:

$3$ and perpendicular

Step-by-step explanation:

It's important to remember that equations of lines are always set up in the format of $y=mx+c$ .

$y$ is the $y$ value, $m$ is the gradient/slope, $x$ is the $x$ value and $c$ is the y-intercept.

Therefore, we must always rearrange our line equations so that $y$ is the subject.

In the first question, we are given the equation $2x+6y=12$ .

We rearrange to make $y$ the subject:

$6y = 12-2x$

Then, we divide both sides by 6 to have the $y$ isolated:

$\frac{6}{6} y = \frac{12}{6} - \frac{2}{6}x\\\\ y = 2 - \frac{1}{3}x$

To find a perpendicular slope, we use the negative reciprocal of the original slope. The negative part of that means we negate the value (it becomes inverse) and the reciprocal part means that we flip the fraction.

So here, the slope is $-\frac{1}{3}$ .

So, the negative reciprocal of that would be $3$ because we inverse the sign (the negative becomes positive) and the fraction is flipped to create $\frac{3}{1}=3$ .

So, the perpendicular slope is $3$ .

In the second question, we have two equations. They both need to be rearranged to isolate the $y$ .

$4x-y=5\\4x = 5 + y\\y = 4x - 5\\\\4y = -x-12\\y = -\frac{1}{4}x - 3$

Look at the slopes of the two equations. If you look carefully, you will see that they are inverse of each other (one is positive and one is negative) and if you imagine $4 = \frac{4}{1}$ , the fraction is flipped.

This means that the values are negative reciprocals of each other, meaning the lines are perpendicular.

5 0

2 years ago