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Charra [1.4K]
3 years ago
11

If x=−24x=−24 and y=6y=6, what is the value of the expression │x+y││x+y│?

Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0
B...
|-24+6|=18
Same for the other one.
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The Marked price of an article is rupees 4500. After allowing some percent of discount and levying 10% VAT it is sold at 4400, f
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Answer:

given,

mp= 4500

now

discount amount=dis%of mp

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sp=mp- discount

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vat=vat%of SP

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now,

sp with vat=sp+vat amount

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now,

4950-90x=4400

or,-90x=-550

or, x=55/9

or, x=6.11%

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What is the value of a?
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David wants to buy a 6-foot long sandwich for a birthday party. If the sandwich costs $72.00, what is the cost per foot?
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$12 per foot

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Find the missing measure for a right circular cone given the following information. Find V if r = 2 and L.A. = 12. (16/3)√2 16√2
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Volume of cone is given by formula

V = \frac{\pi r^{2}h}{3}-------------------------------------------(1)

We are already given r =2, so we need to find h and then we can find volume

So missing meausre is height here ------------------------------------------------------------------------------

To find h we will use lateral area = 12\pi given

Formula for lateral area of cone is \pi r\sqrt{r^{2}+ h^{2}}

so we have12 = \pi r\sqrt{r^{2}+ h^{2}}

Now plug r as 2 in this equation

12 \pi = \pi (2)\sqrt{2^{2}+ h^{2}}

Now solve for h as shown and get h by itself

\frac{12\pi}{2\pi}  = \frac{2\pi\sqrt{4+h^{2}}}{2 \pi}

6  = \sqrt{4+h^{2}}

6^{2}   = \sqrt{4+h^{2}}  ^{2}

36}   = 4+h^{2}36 - 4    = 4+h^{2} -4

32  = h^{2}\sqrt{32} = \sqrt{h^{2}}

\sqrt{16 \times 2} = h\sqrt{16} \times \sqrt{2} = h

4\sqrt{2} = h----------------------------------------------------(2)

Now plug 2 in r place and 4\sqrt{2} in h place in volume formula given in (1)

V = \frac{\pi r^{2}h}{3}

V = \frac{\pi (2)^{2}4\sqrt{2}}{3}     [/tex][tex] V = \frac{\pi (4)4\sqrt{2}}{3}

V = \frac{16 \pi \sqrt{2}}{3}

so choice (1) is right answer

(1)  \frac{16 \sqrt{2}\pi}{3}

correct answer --------------------------------------------------------------------------------------------------

(2)  16 \sqrt{2} \pi

incorrect answer as correct volume answer we got as \frac{16 \sqrt{2}\pi}{3} --------------------------------------------------------------------------------------------------

(3)  4 \sqrt{38} \pi

incorrect answer as correct volume answer we got as \frac{16 \sqrt{2}\pi}{3} --------------------------------------------------------------------------------------------------------

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3 years ago
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