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3 years ago

Order least to greatest 3/40, 4/25, 1/10

Mathematics

2 answers:

Luda [366]3 years ago

7 0

4. 4. 1.
25 20 10

This is the answer

Dafna1 [17]3 years ago

5 0

The answer should be (3/40), (1/10), (4/25).

I found a common denominator for them which is 200 and then times all the numerators and denominators so the denominator was 200, making the fractions go from (3/40),(4/25),(1/10) to (15/200),(32/200),(20/200) then it's easier to put them in order! But make sure to write them in their original value

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A bag contains 3 red marbles, 4 blue marbles, and 6 green marbles. Which pair of events are complementary events? A) choosing a

kotykmax [81]

Answer:

Event D

Step-by-step explanation:

Complementary events are those events that are opposites of each other. i.e. in this case the complementary event for choosing a green marble is not choosing a green. It has nothing to do with choosing or not choosing marbles of colors other than green.

7 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

2. Which of the following points lies in the solution set of the inequality y>/=3x+10?

Alex_Xolod [135]

Sorry if I am wrong I am not 100% sure but I think it’s 3

3 0

2 years ago

How would the sum of cubes formula be used to factor x3y3 + 343? Explain the process. Do not write the factorization.

Svetllana [295]

Answer:

Given : Expression - $x^3y^3+343$

To find : How would the sum of cubes formula be used to factor given expression? Explain the process. Do not write the factorization.

Solution :

The formula of sum of cubes is,

$a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)$

First we convert the given expression in $a^3+b^3$

$x^3y^3+343$

Apply exponent rule : $a^mb^m=(ab)^m$

$x^3y^3=(xy)^3$

Rewrite $343=7^3$

Therefore, $x^3y^3+343$ could be written as $=\left(xy\right)^3+7^3$

On comparison with the formula,

a=xy , b=7

$\left(xy\right)^3+7^3=(xy+7)(xy^2-xy(7)+7^2)$

$\left(xy\right)^3+7^3=(xy+7)((xy)^2-7xy+49)$

5 0

3 years ago

Read 2 more answers

If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]?

kap26 [50]

If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]? f[g(-5)] means substitute -5 for x in the right side of g(x), simplify, then substitute what you get for x in the right side of f(x), then simplify. It's a "double substitution". To find f[g(-5)], work it from the inside out. In f[g(-5)], do only the inside part first. In this case the inside part if the red part g(-5) g(-5) means to substitute -5 for x in g(x) = (x - 3)/2 So we take out the x's and we have g( ) = ( - 3)/2 Now we put -5's where we took out the x's, and we now have g(-5) = (-5 - 3)/2 Then we simplify: g(-5) = (-8)/2 g(-5) = -4 Now we have the g(-5)] f[g(-5)] means to substitute g(-5) for x in f[x] = 2x + 3 So we take out the x's and we have f[ ] = 2[ ] + 3 Now we put g(-5)'s where we took out the x's, and we now have f[g(-5)] = 2[g(-5)] + 3 But we have now found that g(-5) = -4, we can put that in place of the g(-5)'s and we get f[g(-5)] = f[-4] But then f(-4) means to substitute -4 for x in f(x) = 2x + 3 so f(-4) = 2(-4) + 3 then we simplify f(-4) = -8 + 3 f(-4) = -5 So f[g(-5)] = f(-4) = -5

3 0

3 years ago