Answer:
The answer is "Yes".
Step-by-step explanation:
In this question, the answer is "yes" because as the sample group of 50, it is now under the population size of 10 percent, and Often the random sample is less than 30. It doesn't require the standard deviation, and for each of the samples it was selected randomly, therefore randomization becomes achieved.
Answer: David would need 47 1/2 pounds of clay to make 10 pots
Step-by-step explanation:
14 1/4 = 14.25
14.25/3 = 4.75
4.75*10 = 47.5
47.5 = 47 1/2
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer:
f(-1) = 0
f(2) = 16
Step-by-step explanation:
f(-1) = 4(-1) + 4 = 0
f(2) = 4(2) + 8 = 16
