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3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA POINTS.. IM GIVING 40 POINTS !! DONT SKIP :((.

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

(4, 28) (5, 50)

(50 - 28)/(5 - 4)= 22/1 = 22

y - 28 = 22(x - 4)

y - 28 = 22x - 88

y = 22x - 60

zvonat [6]3 years ago

3 0

Equation for linear function.

y=mx+b

We need 2 sets of numbers from the graph to find the slope. Do rise/run or y/x.

(50-28)/(5-4)=22/1=22

so m=22

y=22x+b

Now substitute x and y in to solve for b

28=4*22+b

-60=b

Now we have the equation all ready.

y=22x-60 Done!

If you have any questions just ask in the comment I will get to it as soon as I could.

*Also although I don't really care about points the points I recieve is half the amount you choose to put in so I got 5 points. Although I honestly don't answer questions for points anyway :)

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A park in a subdivision has a triangular shape. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the

pishuonlain [190]

<span>Two adjacent sides of the park say x and y are,
</span><span>x=533feet
y=525feet
A=53º
area=1/2*b*c*sin(A)
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3 0

3 years ago

Read 2 more answers

Please answer this in two minutes

diamong [38]

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

$\frac{XY}{sin(W)} = \frac{WY}{sin(X)}$

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

$\frac{XY}{sin(67)} = \frac{24}{sin(43)}$

Cross multiply:

$XY*sin(43) = 24*sin(67)$

$XY*0.68 = 24*0.92$

Divide both sides by 0.68 to solve for XY

$\frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68}$

$XY = 32.47$

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

6 0

3 years ago

Help Please, anyone good at domain values of composite functions.

Delicious77 [7]

Answer:

second choice

Step-by-step explanation:

$(f \circ g)(x) =$

$= f(g(x))$

$= f(-7x + 7)$

$= \sqrt{-7x + 7 + 3}$

$= \sqrt{-7x + 10}$

Let x = 5:

$(f \circ g)(5) = \sqrt{-7(5) + 10}$

$(f \circ g)(5) = \sqrt{-35 + 10}$

$(f \circ g)(5) = \sqrt{-25}$

Since using x = 5 gives the square root of a negative number, 5 is not in the domain of the composition of the functions.

Answer: second choice

3 0

3 years ago

Which algebraic expression is a polynomial? 4x2 – 3x + StartFraction 2 Over x EndFraction –6x3 + x2 – StartRoot 5 EndRoot 8x2 +

rusak2 [61]

Answer:

The Answer is B

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Consider the following information related to a set of quantitative sample data:

svlad2 [7]

Answer:

(a) There are outliers

(b) $x$ and $x >62$

Step-by-step explanation:

Given

$\sigma = 14.92$

$\bar x = 22.0$

$q_0 = -24$

$q_1 = 14.5$

$q_2 = 24.5$

$q_3 = 33.5$

$q_4 = 64$

Solving (a): Check for outliers

This is calculated using:

$Lower = Q_1 - (1.5 * IQR)$ --- lower bound of outlier

$Upper = Q_3 +(1.5 * IQR)$ --- upper bound of outlier

Where

$IQR = Q_3 - Q_1$

So, we have:

$IQR = 33.5 - 14.5$

$IQR = 19$

The lower bound of outlier becomes

$Lower = Q_1 - (1.5 * IQR)$

$Lower = 14.5 - (1.5 * 19)$

$Lower = 14.5 - 28.5$

$Lower = -14$

The upper bound of outlier becomes

$Upper = Q_3 +(1.5 * IQR)$

$Upper = 33.5 + 1.5 * 19$

$Upper = 33.5 + 28.5$

$Upper = 62$

So, we have:

$-14 \le x \le 62$ --- the range without outlier

Given that:

$q_0 = -24$ --- This represents the lowest data

$q_4 = 64$ --- This represents the highest data

-24 and 64 are out of range of $-14 \le x \le 62$ .

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

$x$ and $x >62$

4 0

2 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA POINTS.. IM GIVING 40 POINTS !! DONT SKIP :((.