Hey :)
This time the answer is quantitive because the mentions numbers
Hope this helps!
Equation: 2K + S --> K2S
Chemical formula: K2S
1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2: M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO: M(CO) = 12.0 +16.0 = 28.0 g/mol
</span>12.0 g H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO
<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover.
CO + 2H2 -------> CH3OH
1 mol 2 mol
given 2.66 mol 6 mol (excess)
How much
we need CO? 3 mol 6 mol
We see that H2 will be leftover, because for 6 moles H2 we need 3 moles CO, but we have only 2.66 mol CO.
So, CO will react completely, and we are going to use CO to find the mass of CH3OH.
3) </span>CO + 2H2 -------> CH3OH
1 mol 1 mol
2.66 mol 2.66 mol
4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 + 4*1.0 + 16.0 = 32.0 g/mol
2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH = 85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
The remaining 3 % are nanomaterials made from e.g. aluminium oxide, barium titanate, titanium dioxide, cerium oxide and zinc oxide. Carbon nanotubes, graphene and fullerenes have annual production amounts in the hundred tonnes range. Nanosilver is estimated to be produced in about 20 tonnes per year.
I looked this up but hope it helps
Answer:

Explanation:
Since all sodium salts and all nitrates are soluble, the insoluble product must be lead(II) bromide.
The equation for the equilibrium is
PbBr₂ ⇌ Pb²⁺ + Br⁻
I/mol·L⁻¹: 0.0140 0.0024
= [Pb²⁺][Br⁻]²
[Pb²⁺] = 0.0140 mol·L⁻¹
[Br⁻] = 0.0024 mol·L⁻¹

