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Anestetic [448]
3 years ago
15

Write the full form of the following LPG and CNG​

Chemistry
2 answers:
mamaluj [8]3 years ago
5 0

Answer:

LPG -Liquefied Petroleum Gas. CNG-Compressed Natural Gas.

May this help you

iris [78.8K]3 years ago
4 0

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>LPG</em><em>=</em><em>Liquified</em><em> </em><em>P</em><em>etroleum</em><em> </em><em>Gas</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Or</em><em>,</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Liquid</em><em> </em><em>petrol</em><em> </em><em>Gas</em>

<em>CNG</em><em>=</em><em>Compressed</em><em> </em><em>Natural</em><em> </em><em>Gas</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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If 5.0 liters H2 (g) at STP is heated to a temperature of 985, pressure remaining constant, the new volume of the gas will be?
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Answer:

V_2=18 \ L \ H_2

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Charles' Law: \frac{V_1}{T_1} =\frac{V_2}{T_2}

Explanation:

<u>Step 1: Define</u>

Initial Volume: 5.0 L H₂ gas

Initial Temp: 273 K

Final Temp: 985 K

Final Volume: ?

<u>Step 2: Solve for new volume</u>

  1. Substitute:                    \frac{5 \ L \ H_2}{273 \ K} =\frac{x \ L \ H_2}{985 \ K}
  2. Cross-multiply:             (5 \ L \ H_2)(985 \ K) = (x \ L \ H_2)(273 \ K)
  3. Multiply:                        4925 \ L \ H_2 \cdot K = 273x \ L \ H_2 \cdot K
  4. Isolate <em>x</em>:                       18.0403 \ L \ H_2 = x
  5. Rewrite:                         x=18.0403 \ L \ H_2

<u>Step 3: Check</u>

<em>We are given 2 sig figs as the smallest. Follow sig fig rules and round.</em>

<em />18.0403 \ L \ H_2 \approx 18 \ L \ H_2<em />

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