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nataly862011 [7]
3 years ago
7

Which step is this ?prophase I, Anaphase I, prophase II, Anaphase II

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:

The correct answer will be prophase I

Explanation:

During this stage, the genetic code is together and hasn't split yet therefore, the answer is prophase I hopefully this helps!

sweet-ann [11.9K]3 years ago
4 0

Answer:

Prophase 1

Explanation:

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Using the equation below, if you have 4.3 mol of nitrogen tribromide and
ankoles [38]

Answer:

sodium hydroxide is the limiting reactant

Explanation:

The first step is usually to put down the balanced reaction equation. This is the first thing to do when solving any problem related to stoichiometry. The balanced reaction equation serves as a guide during the solution.

2NBr3 + 3NaOH = N2 + 3NaBr + 3HOBr

Let us pick nitrogen gas as our product of interest. Any of the reactants that gives a lower number of moles of nitrogen gas is the limiting reactant.

For nitrogen tribromide

From the balanced reaction equation;

2 moles of nitrogen tribromide yields 1 mole of nitrogen gas

4.3 moles of nitrogen tribromide will yield 4.3 ×1/ 2 = 2.15 moles of nitrogen gas

For sodium hydroxide;

3 moles of sodium hydroxide yields 1 mole of nitrogen gas

5.9 moles of sodium hydroxide yields 5.9 × 1/ 3= 1.97 moles of nitrogen gas

Therefore, sodium hydroxide is the limiting reactant.

8 0
2 years ago
Does Mg or Ne have a higher electronegativity value
elena55 [62]

Answer:

Ne

Explanation:

3 0
3 years ago
Read 2 more answers
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=9.31+\log (\frac{0.1359}{0.0655})

pH=9.63

Therefore, the pH of the solution is, 9.63

4 0
3 years ago
What is the ph of a saturated solution of aluminum hydroxide?
sasho [114]
Answer is attached  below ( sorry for mistake )

6 0
3 years ago
Why would you add boiling chips/stones to a solution that is to be refluxed? when should you add them?
anygoal [31]
Answer: Boiling chips provide surfaces on which bubbles can form as the liquid boils.

Hope this helps!
6 0
3 years ago
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