Answer:
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There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Gas constant = 0.0821
Now
<span>PV=nRT
</span>(1.2) * (0.09) = n * (0.0821) * (297)
n = 0.00443
Mass of Butane = 32.105 - 31. 844
= 0.261
Then
Molar mass of Butane gas = 0.261/.00443
= 58.92
Answer:
36.0%.
Explanation:
The mass of water = mass of hydrated copper (II) sulfate - mass of copper (II) sulfate after heating = 4.56 g - 2.92 g = 1.64 g.
The percent by mass of water in the hydrate = (mass of water/mass of hydrated copper (II) sulfate)*100 = (1.64 g/4.56 g)*100 = 35.96% ≅ 36.0%.
To find mol with the 1.3g of NaOH <span>divide it by the weight of NaOH.
</span><span>And convert 250ml into L.
That is 0.250 ml
</span><span>molarity is mol/L = 0.13 mol/L</span>
