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3 years ago

Which molecules are in put in photosynthesis

Physics

2 answers:

Dominik [7]3 years ago

7 0

Answer:

Sunlight, Carbon Dioxide, and Water

Explanation:

Technically minerals are in there too but when I learned this it was just Sunlight, Carbon Dioxide, and Water

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

During the process of photosynthesis, cells use carbon dioxide and energy from the Sun to make sugar molecules and oxygen. These sugar molecules are the basis for more complex molecules made by the photosynthetic cell, such as glucose.

Explanation:

yes.

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The magnetic field in the region between the poles of an electromagnet is uniform at any time, (1 point) but is increasing at th

olga nikolaevna [1]

Answer:

The magnitude of induced emf in the conducting loop is 0.99 mV.

Explanation:

Rate of increase in magnetic field per unit time = 0.090 T/s

Area of the conducting loop = 110 cm^2 = 0.0110 m^2

Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.

Induced e.m.f is given as:

EMF = (-N*change in magnetic field/time)*Area

EMF = rate of change of magnetic field per unit time * Area

EMF = 0.090 * 0.0110

EMF = 0.00099 V

EMF = 0.99 mV

5 0

3 years ago

In your own words describe what free fall is

nekit [7.7K]

Answer:

u are falling

Explanation:

In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

6 0

3 years ago

Read 2 more answers

A spaceship travels toward the Earth at a speed of 0.97c. The occupants of the ship are standing with their torsos parallel to t

Ket [755]

Answer:

Explanation:

We shall apply length contraction einstein's relativistic formula to calculate the length observed by observer on the earth . For the observer , increased length will be observed for an observer on the earth

$L=\frac{.5}{\sqrt{1-(\frac{.97c}{c})^2 } }$

$L=\frac{.5}{.24}$

L= 2.05

The length will appear to be 2.05 m . and width will appear to be .5 m to the observer on the spaceship. . It is so because it is length which is moving parallel to the direction of travel. Width will remain unchanged.

3 0

4 years ago

A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero

qwelly [4]

Answer:

$147.653J = W_f$

Explanation:

We know that:

$E_i - E_f = W_f$

where $E_i$ is the initial energy, $E_f$ is the final energy and $W_f$ is the energy lost due to friction.

so:

$\frac{1}{2}MV^2-0 = W_f$

Where M is the mass and V is the velocity of the runner, so:

$\frac{1}{2}(68.2kg)(4.33m/s)^2 = W_f$

$147.653J = W_f$

7 0

4 years ago

Power of sunlight on Earth The Sun emits about 3.9 * 1026 J of electromagnetic radiation each second. (a) Estimate the power tha

ratelena [41]

Answer:

a)6.34 x $10^{7}$ W/m²

b)1.37 x $10^{3$ W/m²

c) see explanation.

Explanation:

a)The relation of intensity'I' of the radiation and area 'A' is given by:

I= P/A

where P= power of sunlight i.e 3.9 x $10^{26}$ J

and the area of the sun is given by,

A= 4π $R_{sun}$ => 4π $(\frac{1.4*10^{9} }{2} )^{2}$

A=6.15 x $10^{18}$ m²

$I_{sun}$ = 3.9 x $10^{26}$ / 6.15 x $10^{18}$ => 6.34 x $10^{7}$ W/m²

b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space

A= 4π $R$

Now R= 1.5 x $10^{11$ m

A= 4π x 1.5 x $10^{11$ =>2.83 x $10^{23$ m²

The power that each square meter of Earths surface receives

$I_{earth$ = 3.9 x $10^{26}$ /2.83 x $10^{23$ =>1.37 x $10^{3$ W/m²

c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.

6 0

3 years ago