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Rufina [12.5K]
3 years ago
6

Factor the following polynomial completely: 5x^4+20x^3-105x^2

Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Assignment: \bold{Simplify \ Equation: \ 5x^4+20x^3-105x^2}

<><><><><>

Answer: \boxed{\bold{5x^2\left(x-3\right)\left(x+7\right)}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Factor Out Common Term \bold{5x^2}

\bold{5x^2\left(x^2+4x-21\right)}

[ Step Two ] Factor \bold{x^2+4x-21}

\bold{\left(x-3\right)\left(x+7\right)}

[ Step Three ] Rewrite Equation

\bold{5x^2\left(x-3\right)\left(x+7\right)}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

Allushta [10]3 years ago
3 0

Factor 5x4+20x3−105x2

5x4+20x3−105x2

=5x2(x−3)(x+7)

Answer:

5x2(x−3)(x+7)

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morpeh [17]

Answer

You can multiply the first equation by 4 and the second equation by 3.

You can multiply the first equation by 4/3.

You can multiply the first equation by 3.

Explanation

When solving a system of equations by elimination, you want to add or subtract the equations to "get rid" of a variable.

To do that, one of the variables in both equations have to have the same coefficient.

The first answer possible gives x the coefficient of 12 for both equations. You would get 12x+4y=52 and 12x-9y=39. You could subtract those equations to get 13y=13.

The second way gives x the coefficient of 4. You would multiply the first equation by 4/3 to get 4x+4/3y=52/3. You can subtract to get one variable, and then solve from there. Although, multiplying for 4/3 is annoying, so it's not suggested.

You can also "get rid" the the y. Multiply the first equation by 3 to get 9x+3y=39. You can add these equations. When you add 9x+3y=39 and 4x-3y=13 you get 13x=52.

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3 years ago
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prohojiy [21]

Answer:

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Answer:

y(3y - 4)

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