Evaluate (x + y)0 for x = -3 and y = 5. a.) -1/2 b.) 0 c.) 1 d.) 2
2 answers:
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Answer:
Step-by-step explanation:
3 envelopes having 2 red card
2 envelopes having 1 red card and 1 black card
1 envelope having 2 black cards
We are given that . An envelope is selected at random and a card is withdrawn and found to be red.
So, No. of ways of envelope having red card = 3+2 = 5
No. of required ways of envelope having 1 red card and 1 black card = 2
So, probability of getting an envelope having 1 red card and 1 black card =
Hence The chance the other card is black is