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3 years ago

This illustration represents the compoundA)carbon oxide.B)carbon dioxide.C)carbon monoxide.EliminateD)monocarbon oxide.

Physics

2 answers:

pentagon [3]3 years ago

3 0

B.) Carbon Dioxide because the carbon is surrounded by oxygen

maxonik [38]3 years ago

3 0

Answer: The name of the given compound is carbon dioxide.

Explanation:

We are given a compound having 1 carbon atoms and 2 oxygen atoms.

Covalent compound is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound. These are usually formed when two non-metals react.

$CO_2$ is a covalent compound because sharing of electrons takes place between carbon and oxygen atoms. Both the elements are non-metals and hence, will form covalent bond.

The nomenclature of covalent compound is given by:

The less electronegative element is written first, which is carbon.
The more electronegative element is written then (which is oxygen), and a suffix is added with it. The suffix added is '-ide'.
If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on..

So, the name of the given compound is carbon dioxide.

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On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

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3 years ago

The James Webb Space Telescope will be the largest telescope ever put into space and will replace the Hubble Space Telescope. It

Nikolay [14]

Answer:

B : It will avoid the distortion from the atmosphere and give scientists more accurate data

Explanation:

5 0

3 years ago

A sphere of mass of 1.55 kg is accelerated upwards by a string to which the sphere is attached. Its speed increases from 2.81 m/

Mama L [17]

Answer:

The tension in the string is 16.24 N

Explanation:

Given;

mass of the sphere, m = 1.55 kg

initial velocity of the sphere, u = 2.81 m/s

final velocity of the sphere, v = 4.60 m/s

duration of change in the velocity, Δt = 2.64 s

The tension of the string is calculated as follows;

$T = ma + mg\\\\T = m(a + g)\\\\where;\\\\a \ is \ upward \ acceleration \ of \ the \ sphere\\\\g \ is \ acceleration \ due \ to \ gravity =9.8 \ m/s^2\\\\a = \frac{\Delta V}{\Delta t} = \frac{v- u}{ t} = \frac{4.6 - 2.81 }{2.64} = 0.678 \ m/s^2$

T = 1.55(0.678 + 9.8)

T = 1.55(10.478)

T = 16.24 N

Therefore, the tension in the string is 16.24 N

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2 years ago

A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the tempe

Serhud [2]

Answer:

281 K

Explanation:

Charles's Law. V1/T1 = V2/T2.

The temperature must be in K = 21.6°C + 273 = 294.6K.

V1T2 = V2T1.

3.62L x T2 = 3.45L x 294.6K

T2 = (3.45 x 294.6) / 3.62 = 1016.4 / 3.62 = B): 281K.

(By direct proportion of volume change: (3.45L / 3.62L) x 294.6K = 281K).

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2 years ago

Describe two types of volcanic fields please help

spayn [35]

A stratovolcano is a conical volcano consisting of layers of solid lava flows mixed with layers of other rock.

A cinder cone volcano doesn’t have any horizontal layers, and is instead a steep conical hill of tephra that accumulates around and downwind from the vent.

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3 years ago