You arrive in my class 45 seconds after leaving math which is 85 meters away. How fast did you travel?

Why might you want to use a single fixed pulley?

hjlf

A single fixed pulley can be used to raise or lower lightweight objects.

Option b

Explanation:

A pulley is a simple machine tool which is used to make lifting or lowering tasks easy. A single fixed pulley is a system involving only one pulley fixed on a constant rigid support with a rope wrapped around the wheel. Such a system can be used only to change the direction of applied force in raising or lowering small, lightweight objects which need minimal work force.

A single fixed pulley system helps only in redirecting the applied force direction by using a rope and wheel assembly. The work done in such a case remains the same and hence it is not preferred to use it in lifting heavy objects. Neither is the required force reduced in case of a single fixed pulley system. A movable pulley helps in achieving (A) and (C).

4 0

3 years ago

A certain sound is recorded by a microphone. The same microphone then detects a second sound, which is identical to the first on

katrin [286]

Answer:

Loudness of the second sound is more than the first one.

Explanation:

There are two sounds, the second sound is identical to first but the loudness of second is more than the first one.

As the frequency is same so the itch is same for both the sounds.

As the loudness depends on the amplitude of the sound so the loudness of the second sound is more than the first sound.

8 0

2 years ago

Which characteristics define a liquid?

Artemon [7]

Undefined shape, particles or atoms are loose, wet

3 0

2 years ago

A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/

torisob [31]

Answer:

The constant angular acceleration of the wheel is 12.16 rad/s²

Explanation:

Given;

initial angular distance, θ = 28

time of the motion, t = 5 s

initial angular velocity is calculated as;

$\omega _i = \frac{\theta}{t} = \frac{28}{5}.\frac{rev}{s} \ \times \ \ \frac{2 \pi \ rad}{1 \ \ rev} = 35.19 \ rad/s$

final angular velocity is given as, $\omega _f = 96.0 \ rad/s$

The constant angular acceleration is calculated as;

$\alpha = \frac{\omega _f - \omega _i}{t} \\\\\alpha = \frac{96 - 35.19}{5} \\\\\alpha = 12.16 \ rad/s^2$

Therefore, the constant angular acceleration of the wheel is 12.16 rad/s²

6 0

2 years ago

Three identical very dense masses of 3500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,

larisa86 [58]

Answer:

A) 7.37 x 10^-4 N

B) The resultant force will be towards the -x axis

Explanation:

The three masses have mass = 3500 kg

For the force of attraction between the mass at the origin and the mass -100 cm away:

distance r = 100 cm = 1 m

gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2

Gravitational force of attraction $F_{g}$ = $\frac{Gm^{2} }{r^{2} }$

where G is the gravitational constant

m is the mass of each of the masses

r is the distance apart = 1 m

substituting, we have

$F_{g}$ = $\frac{6.67*10^{-11}*3500^{2} }{1^{2} }$ = 8.17 x 10^-4 N

For the force of attraction between the mass at the origin and the mass 320 cm away

distance r = 320 cm = 3.2 m

$F_{g}$ = $\frac{Gm^{2} }{r^{2} }$

substituting, we have

$F_{g}$ = $\frac{6.67*10^{-11}*3500^{2} }{3.2^{2} }$ = 7.98 x 10^-5 N

Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = 7.37 x 10^-4 N

B) The resultant force will be towards the -x axis

7 0

3 years ago