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3 years ago

Hank estimated the width of the door to his class room in feet what is a reasonable estimate

1 answer:

4 0

My reasonable estimate might be about 2 1/2 feet. I know that because taking three rulers up to your bedroom or a normal room and get about 2 or 2 1/2 feet

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Given radical a and radical b are in simplest radical form and radical a timed radical b equals c radical d and c radical d is i

lawyer [7]

Answer:

See below.

Step-by-step explanation:

Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.

ab = c^2d

Example:

Let a = 6 and let b = 10.

sqrt(6) and sqrt(10) are in simplest radical form.

Now we multiply the radicals.

sqrt(a) * sqrt(b) = sqrt(6) * sqrt(10) = sqrt(60) = sqrt(4 * 15) = 2sqrt(15)

We have c = 2 and d = 15.

ab = c^2d

6 * 10 = 2^2 * 15

60 = 60

Our relationship between a, b and c, d works.

6 0

3 years ago

Please help!!! How do I write an expression for this???

lbvjy [14]

4x + 2
Eg 4 times 2 =8 +2 =10

3 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

The inequality below represents h, the number of hours Ellie need to work this week to earn at least $360 by the end of the mont

Gnom [1K]

Answer:

The answer to your question is 10 hours.

Step-by-step explanation:

Inequality 12h + 240 > 360

Solve the inequality as if it was an equation

12h > 360 - 240

12h > 120

h > 120 / 12

h = 10 hours

Let's evaluate some number of hours

If h = 3 12(3) + 240 > 360

36 + 240 > 360

276 > 360 Incorrect, she needs to work more

than 3 hours

If h = 5 12(5) + 240 > 360

60 + 240 > 360

300 > 360 Incorrect, she needs to work more

than 5 hours

If h = 7 12(7) + 240 > 360

84 + 240 > 360

324 > 360 Incorrect she needs to work more

than 7 hours

If h = 11 12(11) + 240 > 360

132 + 240 > 360

372 > 360 Correct, she needs to work at least

10 hours.

7 0

3 years ago

Suppose the population of a town is 98,000 in 2014. The population increases at a rate of 3.7 percent every year. What will the

Setler [38]

Answer: 121871

Step-by-step explanation:

Current population = 98000

Rate of increase = 3.7% / year

Total time = 2020 - 2014 = 6 years

Population in 2020 = 98000 * (1+ (3.7/100))^6

= 98000 * (1.037)^6 = 98000 * 1.243576 = 121870.505

Rounding off to nearest whole number we get the population = 121871

3 0

3 years ago