In a series circuit, the current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.
Answer:
the answer is c
Explanation:
a chemical change mean it changes it for ever and a physical change mean it can be changed back and evaporation means it turns solid water in to gas hope this helps
Answer:
B. A covalent bond has a lower potential energy than the two separate atoms.
Explanation:
<em>Identify the correct statement. </em>
<em>A. It is not possible for two atoms to share more than two electrons.</em> FALSE. Atoms also can share 4 electrons (double bond) or 6 electrons (triple bond).
<em>B. A covalent bond has a lower potential energy than the two separate atoms.</em> TRUE.
<em>C. Single bonds are shorter than double bonds.</em> FALSE. Single bonds are longer than double bonds.
<em>D. A covalent bond is formed through the transfer of electrons from one atom to another.</em> FALSE. In covalent bonds, electrons are shared, not transferred from one atom to another.
<em>E. A pair of electrons involved in a covalent bond are sometimes referred to as lone pairs.</em> FALSE. Lone pairs are those that do not participate in a bond.
Answer:
The question is incomplete and confusing.
- In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.
- In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.
See below the details.
Explanation:
Which compound will not form ions?
<u />
<u>1. Write the balanced molecular equation:</u>
- Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)
<u />
<u>2. Write the ionizations for the ionic aqueous compounds:</u>
<u />
- Pb(NO₃)₂(aq) → Pb⁺²(aq) + 2NO₃⁻(aq)
- 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)
- 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)
<u />
<u>3. Write the complete ionic equation:</u>
Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.
All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.
It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.
