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3 years ago

11

Guys, please help I'm stuck on this.

2 answers:

Shtirlitz [24]3 years ago

8 0

Answer is b good luck

jok3333 [9.3K]3 years ago

7 0

The answer is letter B :)

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2 years ago

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Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.

Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= $moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.241}{0.0137kg}=17.6mole/kg$

Therefore, the molality of solution is 17.6 mole/kg

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3 years ago