Answer:
Explanation:
Hello,
In this case, the chemical reaction is:
Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:
In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:
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Explanation:
(A) As we know that carbonic acid () and Sodium bicarbonate (
) forms an acidic buffer.
Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.
pH = ........... (1)
So mathematically, if [Salt] = [Acid] then = 1
.
And, = 0
Therefore, equation (1) gives us the following.
pH = (when acid and salt are equal in concentration)
Hence, of
(carbonic acid) is 6.35.
And, with this we have following results.
In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].
Hence, for the cases pH = = 6.35.
(B) = 0.045 M and,
= 0.45 M
Hence, pH =
=
= 6.35 + (-1)
= 5.35
Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.
(C) = 0.45 M
= 0.045 M
So, pH =
=
= 6.35 + (+1)
= 7.35
This means that pH on Basic side makes it no more acidic buffer.