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Umnica [9.8K]
3 years ago
8

What is the velocity of a dropped object after it has fallen for 3.0 seconds?

Physics
1 answer:
7nadin3 [17]3 years ago
3 0
As a consequence, gravity will accelerate a falling object so its velocity increases 9.81 m/s or 32 ft/sfor every second it experiences free fall. Velocity (v) can be calculated via v = gt, where g represents the acceleration due to gravity and t represents time in free fall.
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Under certain conditions, it is possible to get more work out of a machine than you put into it.
Iteru [2.4K]
IF that were true, then you could take some of the work from the output,
put it back into the input to keep the machine running, and use the rest
to run the lights and the hot water heater in your house.  That way, you'd
never need to buy energy from the electric company.

You NEVER get more work out of a machine than you put into it.
Never never never.

(Unless there's a battery or a tiny gasoline engine or a hamster
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7 0
3 years ago
The bending of light as it passes into a transparent material of different optical intensity is known as
defon
The bending of light as it passes into a transparent material of different optical intensity is known as refraction. The correct option among all the options given in the question is option "C".It can never be reflection as reflection is the bouncing of the light from a surface and so option “A” can easily be negated. The last option or option “D”<span> conversion and it mean converting something to another and that means a total change of form. So the last option should also be negated. The second option can also be negated.</span>
5 0
3 years ago
An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0
ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure  = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

T_{H} = 62.9 °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

T_{L} = - 10.1 °c = 262.9 K

COP of the system is given by

COP = \frac{T_{L} }{T_{H} -T_{L}   }

COP = \frac{335.9}{335.9 -262.9}

COP = 4.6

Therefore the COP of the system is = 4.6

8 0
3 years ago
A 3.5 V battery is connected to a wire with a resistance of 2.5 Ohms. Use Ohm's law to calculate the current for this wire
Dafna11 [192]
1.4 should be the answer
5 0
3 years ago
Read 2 more answers
Images produced by a cathode ray tube result from induced emf True or false
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I'm not completely sure but i think it's false 
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3 years ago
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