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3 years ago

What is the velocity of a dropped object after it has fallen for 3.0 seconds?

1 answer:

3 0

As a consequence, gravity will accelerate a falling object so its velocity increases 9.81 m/s or 32 ft/sfor every second it experiences free fall. Velocity (v) can be calculated via v = gt, where g represents the acceleration due to gravity and t represents time in free fall.

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A puck of mass 0.5100.510kg is attached to the end of a cord 0.8270.827m long. The puck moves in a horizontal circle without fri

yanalaym [24]

Answer: 2.75 1/sec

Explanation:

The only external force (neglecting gravity) acting on the puck, is the centripetal force, which. in this case, is represented by the tension in the string, so we can say:

T = mv² / r (1)

Our unknown, is the frequency at which the puck can go around the circle, which is the inverse of the period Tp.

By definition, a period is the time needed by the puck to complete one entire circle.

By definition also , angular velocity is the rate of change of the angle advanced, so we can express this way:

ω = ∆θ / ∆t

The angle advanced during one period, is exactly (by angle definition) 2 π radians.

So, we can always write the angular velocity, ω, as follows:

ω = 2π / Tp = 2πf

Now, there is a relationship between linear and angular velocity, that can be found applying simply the definition of velocity and of an angle too, as follows:

v = ∆s / ∆t = r ∆θ/∆t = ω r

Replacing in (1), we have:

T = mω2 r2 / r = m ω2r (2)

We have just found that ω= 2πf, so, replacing in (2) :

T = m (2π)2 f2 r

Solving for f:

f = 1/2π√(T/mr) = 1/2π 17.28 1/sec = 2.75 1/sec

6 0

3 years ago

While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c

Dmitriy789 [7]

<h2>Answer:</h2>

<u>A) Increase the voltage by adding a bigger battery </u>

<h2>Explanation:</h2>

According to Ohm's law

V = IR

where V is voltage, I is current and R is the resistance. If we write the equation for resistance we would get

R= V / I

Here we can see that Voltage is directly proportional to Resistance so in order to keep the balance if we increase the resistance then we must increase the voltage to keep the current constant.

4 0

3 years ago

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A group of students collected the data shown below while attempting to measure the coefficient of static friction (of course, it

anzhelika [568]

Answer:

0.130

Explanation:

From the given data, the coefficient of static friction for each trial are:

1. 0.053

2. 0.081

3. 0.118

4. 0.149

5. 0.180

6. 0.198

The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

= 0.779

So that;

the average coefficient of static friction = $\frac{sum of coefficient of static friction}{number of trials}$

= $\frac{0.779}{6}$

= 0.12983

The average coefficient of static friction is 0.130

8 0

3 years ago

If an incident light ray hits a flat smooth object at 28 degrees, it will reflect off at an angle of…

Nookie1986 [14]

Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.

Hence, option B is correct

To learn more about the law of reflection, refer to the link;

brainly.com/question/12029226

#SPJ1

5 0

2 years ago

Which statements about electric field lines are correct? Check all that apply.

pochemuha

They point towards a negative charge.
They point away from a positive charge.
They never cross.

3 0

3 years ago

Read 2 more answers