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ad-work [718]
4 years ago
11

A student pulls a 60.-newton sled with a force

Physics
2 answers:
ikadub [295]4 years ago
6 0

The magnitude of force exerted by the sled on the student is \boxed{20\text{ N}}.

Explanation:

Given:

The weight of the sled is 60\text{ N}.

The force applied by the student on the sled is 20\text{ N}.

Concept:

According to the Newton's third law of motion, each and every action on a body applies a equal and opposite reaction on the other body. It means if a person pulls a body by a force then the body also pulls the person with the same force towards itself.

The direction of the reaction applied by the body on the person will be opposite to the action of the person on the body.

In the same manner, as the student applies a force on the sled to pull it in the forward direction, the sled will also apply the same magnitude of force on the student to pull him back in the opposite direction.

<u>The weight of the sled acts in the vertically downward direction and therefore, it will not play any role in the reaction force of the sled on the student.</u>

Thus, the magnitude of force exerted by the sled on the student is \boxed{20\text{ N}}.

Learn More:

1. Which one remains constant in uniform circular motion brainly.com/question/2562955

2. The unit of the gravitational constant brainly.com/question/1724648

3. The x-component of the given vector brainly.com/question/2562517

Answer Details:

Grade: High School

Subject: Physics

Chapter: Laws of motion

Keywords:

student, pulls, a sled, magnitude of force, action, reaction, newton's third law, exerts, applies a force, opposite direction.

OLEGan [10]4 years ago
5 0
20 N

Newtons third law states that any action (pulling the sled) has an equal and opposite reaction (the sled pulling back on you).
Think about pulling a sled on really slippery ice, you would pull yourself toward the sled just as much as the sled toward you.
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ludmilkaskok [199]

Answer:

k = 0.5 MN/m

Explanation:

Mass of the railcar, m = 5000 kg

Speed of the rail car, v = 1 m/s

The Kinetic energy(KE) of the railcar is given by the equation:

KE = 0.5 mv²

KE = 0.5 * 5000 * 1²

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The potential energy(PE) stored in the spring is given by the equation:

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