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Vlad1618 [11]
3 years ago
8

What is the voltage of the electrochemical cell written as: Cu(s) | Cu2+(aq) || Mg2+(aq) | Mg(s)?

Physics
1 answer:
erma4kov [3.2K]3 years ago
4 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  
<span><span>The best and most correct answer among the choices provided by the question is  </span>B.-2.71 V.</span>  
Mg2+(aq) + 2e- -> Mg(s) E=-2.37 V  

Cu2+(aq) + 2e- -> Cu(s) E =+ 0.34 V  

Since Cu is acting as the anode, the equation needs to be reversed.  

Cu(s) -> Cu2+(aq) + 2e- E =- 0.34 V  

Ecell= -2.37 V+ (- 0.34 V) = -2.71 V   <span><span>

</span><span>Hope my answer would be a great help for you. </span> </span> <span> </span>
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