The acceleration of the object after 3 seconds of fall is -9.8 m/s².
The given parameters;
- initial velocity of the object, u = 0
- time of motion of the object, t = 3 seconds
Acceleration is the change in velocity per change in time of motion.
The acceleration of the object after 3 seconds of fall is calculated as follows;
- Since the object is in free fall, the object experiences only acceleration due to gravity.
- the magnitude of this acceleration due to gravity is 9.8 m/s²
- the direction of this acceleration is downwards
Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².
Learn more here: brainly.com/question/13197713
Answer:
snow is 64.638 kg / hr
Explanation:
Given data
wide w = 21 feet
long L = 20 ft
area A = 1350 square foot
mass of snow m = 1.90 mg
to find out
snow in kilograms / hour
solution
we will find snow in kg
so we apply formula that is
snow kg / hour = w × L ×A × m × 60/10^6
put all value we get snow
snow = 21 × 20 × 1350 × 1.90 × 60/10^6
snow = 420 × 1350 × 1.90 × 60/10^6
snow = 1077300 × 60/10^6
snow = 64.638
hence snow is 64.638 kg / hr
Their linear inertia is equivalent to their masses. Let the inertia of the first moose be m₁ and the second be m₂.
m₁u + m₂u = (m₁ + m₂) x 1/3 u
3m₁ + 3m₂ = m₁ + m₂
3 m₁/m₂ + 3 = m₁/m₂ + 1
m₁/m₂ = 2
The ratio of their inertias is 2
