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2 years ago

14

Một ô tô chuyển động từ A đến B với tốc độ 30m/s rồi lập tức quay lại A với tốc độ 20m/s. Tính tốc độ trung bình trên cả đoạn đi

và về

1 answer:

viktelen [127]2 years ago

4 0

54 plus 95 is the real answer 3 is everyone’s lucky number one lucky leprechaun is the kind and two daughters are his wives

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If i like a boy and he dont like me what should i do? If we like each other what should i do?

crimeas [40]

Answer:

If he doesn't like you then hang out with him more but if he does then try to keep your cool

Explanation:

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3 years ago

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The compass uses a pendulous system to improve?

ivanzaharov [21]

The compass is designed and developed to use a pendulous system to improve horizontality.

<h3>What is a compass?</h3>

A compass can be defined as a scientific instrument that contains a magnetized pointer, which is used to show and indicate the following four (4) main cardinal directions:

North (N)

South (S)

West (W)

East (E)

Basically, the compass is a scientific instrument that's designed and developed to use a pendulous system to improve horizontality.

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2 years ago

How much time would Simpson save by increasing his average velocity to 26m/s East?

igor_vitrenko [27]

Answer:

8 minutes

Explanation:

Part of the question is missing. Complete question is:

<em>Simpson drives his car 144 km with an average velocity of 24 m/s toward the east. How much time would Simpson save by increasing his average velocity to 26m/s East?</em>

Solution:

First of all, we have to calculate the time it takes for Simpson to complete the drive moving at the initial velocity, 24 m/s. We can use the formula:

$t=\frac{d}{v}$

where

$d=144 km = 1.44\cdot 10^5 m$ is the displacement

$v=24 m/s$ is the velocity

Substituting,

$t=\frac{1.44\cdot 10^5}{24}=6000 s = 100 min$

While driving at 26 m/s, the time taken will be

$t=\frac{1.44\cdot 10^5}{26}=5538 s=92 min$

So, Simpson will save 8 minutes.

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3 years ago

It is important that your muscles are very warm when doing this type of stretching.

MaRussiya [10]

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3 years ago

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The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t

Bumek [7]

Answer:443.1 s

Explanation:

Given

Engine of a locomotive exerts a force of $8.1\times 10^5 N$

Mass of train $=1.9\times 10^7$

Final speed (v) $=68 km/h \approx 18.88 m/s$

F=ma

so $acceleration(a) =\frac{F}{m}=\frac{8.1\times 10^5}{1.9\times 10^7}$

$a=0.042631 m/s^2$

and acceleration is

$a=\frac{v-u}{t}$

$0.042631=\frac{18.88-0}{t}$

$t=443.089 \approx 443.1 s$

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3 years ago

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