-2x(x-3) = -11
-2x(x) -2x(-3) = -11
-2x² + 6x = - 11
-2x² + 6x + 11 = 0
Let us use the quadratic formula in solving for the value of x.
-2x² + 6x + 11 = 0
a = -2 ; b = 6 ; c = 11
x = (-b <u>+</u> √b² -4ac) ÷ 2a
x = (-6 + √6² - 4(-2)(11)) ÷ 2(-2)
x = (-6 + √36 + 88) ÷ -4
x = (-6 + √124) ÷ -4
x = (-6 + 11.14) ÷ -4
x = 5.14 ÷ -4
x = -1.285 or -1.29
x = (-6 - 11.14) ÷ -4
x = -17.14 ÷ -4
x = 4.285 or 4.29
Answer:
surface area is=2πr×r+πdh
<h3>
Answer: -1</h3>
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Explanation:
First we need to find the slope of this given line.
The two points on here are (0,-3) and (3,0)
Apply the slope formula
m = (y2-y1)/(x2 - x1)
m = (0-(-3))/(3-0)
m = (0+3)/(3-0)
m = 3/3
m = 1
The slope of the given line is 1. The negative reciprocal of this is -1, which is the perpendicular slope.
Side Note: Any two perpendicular lines always have their slope multiply to -1, as long as neither line is vertical.
Answer:
Step-by-step explanation:
7
Answer:
At either b = -12 or b = +14, the equation has a unique solution.
Step-by-step explanation:
The quadratic equation w^2 + bw + 36 = 0 has three coefficients: a = 1, b and c = 36. This equation will have a unique solution (which is also real, not complex) if the discriminant b^2 - 4ac is zero. Here b^2 - 4ac can be rewritten as
b^2 - 4(1)(36). Setting this equal to zero, we get
b^2 - 144 = 0, which is equivalent to b^2 = 144. Thus, b = ± 12.
At either b = -12 or b = +14, the equation has a unique solution.