Answer:
x = 14
Step-by-step explanation:
Assuming that EF and FG are both straight lines that sum up to EG, then:
EF + FG = EG
(4x + 15) + 39 = 110
4x + 54 = 110
4x = 56
x = 14
The y answers would be 11, 8, 5, 2, -1.
To find these parts of the table, we simply put the x value in for x and solve for y. The first two are done for you below.
WHEN x = -2
y = -3x + 5
y = -3(-2) + 5
y = 6 + 5
y = 11
WHEN x = -1
y = -3x + 5
y = -3(-1) + 5
y = 3 + 5
y = 8
Answer:
You have to make a frequency table.
Step-by-step explanation:
The classes are
.320- .329
.330-.339
.340 - .349
.350 - .359
.360 - .369
Then, you have to find to find how many values would fall into the class of .340 - .349.
<h2>Classes are basically compound inequalities. </h2>
.320 ≤ x ≤.329
All x values that are less than (or equal to) .329 but greater than .320 fall into the class of
.320- .329.
Frequency is just how many numbers are in a class.
The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is
<u>Solution:</u>
Given, line equation is 4x – 3y = 10
We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)
Now, let us find the slope of the given line,
We know that, slope of a line slope of perpendicular line = -1
Now, slope of our required line = and it passes through (-2, 4)
<em><u>The point slope form is given as:</u></em>
Hence the equation of line is found out