WILL GIVE BRAINLIEST!!!

Suppose Jessica opens a savings account with $5000 that compounds interest daily. The APR at the time Jessica opens the account

IrinaK [193]

Hi there

1+0.035=(1+r/360)^360
Solve for r
R=(((1.035)^(1÷360)−1)×360)×100
R=3.44%

6 0

3 years ago

Robert is building a deck in his backyard. Each piece of wood measures 42.5 inches. If he has 86 boards,how long are they altoge

BlackZzzverrR [31]

You multiply 86 by 42.5 because each board is 42.5 and there are 86 boards.

4 0

3 years ago

Write these numbers as fractions. Simplify the answers. 0.5, 12.3, 0.07, 0.625

motikmotik

0.5 => 5/10 => 1/2

12.3 => 123/10

0.07 => 7/100

0.625 => 625/1000 => 25/40 => 5/8

4 0

3 years ago

Read 2 more answers

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

What is -6x plus 18 equals -6

Neporo4naja [7]

It’s going to be -18

First add 6 to both sides to get x by itself

-6x + 18 = -6
+6 +6

X + 18 = 0

Then minus the 18 giving you x = -18

7 0

3 years ago