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Serjik [45]
3 years ago
8

Solve by factoring 7b^2-8b+3=2

Mathematics
2 answers:
Ahat [919]3 years ago
6 0
7b^2-8b+3=2 \\ 7b^2-8b+1=0 \\ (7x-1)(x-1)=0 \\ x=1 \\ x= \frac{1}{7}
mixas84 [53]3 years ago
5 0
Subtract the 2 over from the 3 which leaves you with 1 as the constant. Then you have 7b^2-8b+1. Slide the 7 over to the 1 using the slide and divide method. This leaves you with b^2-8b+7. Then just think "what multiplies to get 7, and adds to -8." The answer to that is (x-7)(x-1). Then you have to divide by 7 because you slid it earlier. So that gives you the answer of : (x-1)(7x-1).
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What method would you choose to solve the equation 2x^2-7=9
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Here is one way to solve for x.

Step 1)  2x^2-7=9

Step 2)  2x^2-7+7=9+7

Step 3)  2x^2=16

Step 4)  (2x^2)/2=16/2

Step 5)  x^2=8

Step 6)  sqrt(x^2)=sqrt(8)

Step 7)  |x|=sqrt(8)

Step 8)  x=sqrt(8) or x=-sqrt(8)

-------------------------------------

Below are explanations/reasons to each of the steps above.

Step 1) Original equation

Step 2) Add 7 to both sides

Step 3) Combine like terms

Step 4) Divide both sides by 2

Step 5) Simplify

Step 6) Apply the square root to both sides. The notation "sqrt" is shorthand for "square root"

Step 7) Use the rule that sqrt(x^2) = |x| for all real numbers x

Step 8) Use the rule that if |x| = k then x = k or x = -k for some fixed number k.

-------------------------------------

The two solutions are
x = sqrt(8) or x = -sqrt(8)

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3 years ago
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No. See explanation  below.

Step-by-step explanation:

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The answer is B.
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