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Zigmanuir [339]
3 years ago
5

Which of the following statements are true of the discriminant?

Mathematics
2 answers:
sasho [114]3 years ago
7 0

Answer:

The correct options are A, C and D.

Step-by-step explanation:

We know that,

<em>The quadratic formula for the quadratic equation ax^2+bx+c=0 is x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}.</em>

Now, we have,

The discriminant is D=b^2-4ac.

So, from the options, we get that,

The true statements for the discriminant are,

A: The discriminant is D=b^2-4ac in the quadratic formula.

C: The discriminant is the radicand of the quadratic formula.

D: The discriminant is the value under the radical in the quadratic formula.

OverLord2011 [107]3 years ago
3 0

Answer:

The answer is A,C,D

Step-by-step explanation:


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I need help on this pleasee and please explain​
Sophie [7]

Answer:

Undefined

Step-by-step explanation:

Use the formula y2-y1/x2-x1

3-9/-5-(-5)

-6/0

Any number with a denominator of 0 is undefined

3 0
2 years ago
1. A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts o
Sauron [17]

Answer:

The confidence interval estimate of the population mean is :

(0.61 ppm, 0.90 ppm)

The correct option is (A).

Step-by-step explanation:

The amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city are:

S = {0.58, 0.82, 0.10, 0.98, 1.27, 0.56, 0.96}

A (100-\alpha )\% confidence interval for the population mean (μ) is an interval estimate of the true value of the mean. This interval has a (100-\alpha )\% probability of consisting the true value of mean.

⇒ Since the population standard deviation is not provided we will use the <em>t</em>-distribution to construct the 99% confidence interval for mean.

⇒ The formula for confidence interval for the population mean is:

                                          \bar x\pm t_{\alpha/2,(n-1)}\times \frac{s}{\sqrt{n}}

Here,

\bar x = sample mean

<em>s </em>= sample standard deviation

<em>n</em> = sample size

t_{\alpha/2,(n-1)} = critical value.

The degrees of freedom for the critical value is, (<em>n</em> - 1) = 7 - 1 = 6.

The significance level is: \alpha =1-Confidence\ level=1-0.99=0.01

The critical value is:

t_{\alpha/2,(n-1)}=t_{0.01/2, 7}=t_{0.05,7}=3.143

**Use the <em>t</em>-table for the critical value.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{7}(0.58+ 0.82+ 0.10+ 0.98+ 1.27+ 0.56+ 0.96) =0.753

\int\limits^a_b {x} \, dx s=\sqrt{\frac{\sum (x{i}-\bar x)^{2}}{n-1} } =\sqrt{\frac{1}{6} \times 0.859743} =0.379

The 99% confidence interval for μ is:

x^{2} CI=0.753\pm 3.143\times\frac{0.379}{\sqrt{7}} \\=0.753\pm0.143\\=(0.61, 0.896)\\\approx(0.61, 0.90)

The confidence interval estimate of the population mean is:

(0.61 ppm, 0.90 ppm)

The upper and lower limit of the 99% confidence interval indicates that the true mean value is less than 1 ppm. This implies that there is not too much mercury in tuna sushi

Because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Thus, the correct option is (A).

6 0
3 years ago
The graph below is correct for the linear equation y=-3. <br><br> True<br> False
Oksana_A [137]

Answer:

False.

Step-by-step explanation:

The graph that is shown is correct for the equation x= -3. The graph for y= -3 would run vertically, not horizontally.

6 0
3 years ago
Read 2 more answers
I'll show a pic of my question​
Hunter-Best [27]

Answer:

Umm I think you forgot to send the pic with this question  

Step-by-step explanation:

Hope I can help next time!!!!!!

7 0
3 years ago
I need help with this question. I didn't choose answer D, but I accidentally did. If you could help me, that would be great.
Alex

Answer:

The correct answer would be B

Step-by-step explanation:

Plz Mark Brainlist

7 0
3 years ago
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